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odedra.vijay05
 Post subject: How to select a List<Map> with HQL
PostPosted: Mon Aug 01, 2016 3:52 am 
Newbie

Joined: Mon Aug 01, 2016 3:47 am
Posts: 2
I have requirement where I run select query with 50+ fields. HQL returns fields with different name than in db/pojo class. I cannot pass alias for all 50+ fields. So is there any way I can get all fields where names are same as db/pojo class. I transform result in List<Map>.
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vlad
 Post subject: Re: HQL keep column names as alias
PostPosted: Mon Aug 01, 2016 10:43 am 
Hibernate Team
Hibernate Team

Joined: Thu Sep 11, 2014 2:50 am
Posts: 1628
Location: Romania
You can use HQL support for map results:

Code:
List<Map> phoneCallTotalDurations = entityManager.createQuery(
    "select new map(" +
    "    p.number as phoneNumber , " +
    "    sum(c.duration) as totalDuration, " +
    "    avg(c.duration) as averageDuration " +
    ")  " +
    "from Call c " +
    "join c.phone p " +
    "group by p.number ", Map.class )
.getResultList();
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odedra.vijay05
 Post subject: Re: How to select a List<Map> with HQL
PostPosted: Tue Aug 02, 2016 2:25 am 
Newbie

Joined: Mon Aug 01, 2016 3:47 am
Posts: 2
Thank you for your reply.

But I do not want to specify all the database fields in query. This is what I need,

Query query = session.createQuery("from Customer");
List<Map> list = query.list();
and map needs to have key as db field name or pojo variable name.

Map map = list.get(0);
map.get("customer_name"); //I want to get info in this way.
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vlad
 Post subject: Re: How to select a List<Map> with HQL
PostPosted: Tue Aug 02, 2016 3:04 am 
Hibernate Team
Hibernate Team

Joined: Thu Sep 11, 2014 2:50 am
Posts: 1628
Location: Romania
Hibernate does not offer this possibility. After all, there is a very good reason why we are mapping entities to tables.
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