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 Post subject: How write custom join clause in one-to-many mapping
PostPosted: Wed Jun 29, 2016 7:00 am 
Newbie

Joined: Wed Jun 15, 2016 2:38 am
Posts: 4
I have 2 tables repository and repository_credential_assn (relationship is one to many)


Repository

id
name


repository_credential_assn
repository_id
credential_id
is_default

I want to get all repository list info and those credential_id which is_default = true

Code:
@Entity
@Table(name="repository")
@SecondaryTable(name = "repository_credential_assn", pkJoinColumns=@PrimaryKeyJoinColumn(name="repository_id", referencedColumnName="id"))
public class RepositoryDom implements Serializable {
   
   @Id
   @Column(name="id")   
   private int id;
   
   @Column(name = "name")
   private String name;      

        @Column(name="credential_id", table="repository_credential_assn")
   @WhereJoinTable(clause = "is_default = true")
   private Integer defCredId;


Select should be as follows:

Code:
select r.id, r.name, rca.credential_id
from repository r left outer join repository_credential_assn rca on r.id = rca.repository_id and is_default =true


But @WhereJoinTable does not work 'and is_default =true' condition does not add. How can I solve the problem ?


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 Post subject: Re: How write custon join clause
PostPosted: Wed Jun 29, 2016 8:24 am 
Hibernate Team
Hibernate Team

Joined: Thu Sep 11, 2014 2:50 am
Posts: 1630
Location: Romania
The SecondaryTable works only for tables whose rows are in a one-to-one relationship. In your case, there is a one-to-many association, so the mapping is wrong.

1. You need to map Repository and RepositoryCredentialAssn as individual entities
2. In RepositoryCredentialAssn, you need to have:

Code:
@ManyToOne
@JoinColumnsOrFormulas(
{
    @JoinColumnOrFormula(column=@JoinColumn(name="repository_id", referencedColumnName="id")),
    @JoinColumnOrFormula(formula=@JoinFormula(value="true", referencedColumnName="is_default"))
})
private Repository repository;


3. Then, in Repository you have the bidirectional one-to-many side:

Code:
@OneToMany(mappedBy = "repository", cascade = CascadeType.ALL, orphanRemoval = true)
private List<RepositoryCredentialAssn> credentials = new ArrayList<>();


So you can access the RepositoryCredentialAssn like this:

Code:
Repository repository - entotuManager.find(Repository.class, repositoryId);
List<RepositoryCredentialAssn> credentials = repository.getCredentials();


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