Hello,

I'm trying to build a parameterized typed query.
i've been trying to follow the (too numerous) tutorials online and i cannot figure out what i am doing wrong.
I'm getting IllegalArgumentException: Unaware how to convert value [org.hibernate.ejb.criteria.expression.ParameterExpressionImpl@48d86fa8 : org.hibernate.ejb.criteria.expression.ParameterExpressionImpl] to requested type [java.lang.Long] when trying to do this:

Parameter<Long> keyParameter = cb.parameter(Long.class);
Predicate idPredicate = cb.equal(query.from(MyEntity.class)
.<Long> get(MyEntity_.id), idParameter); //exception thrown Here

Hibernate is trying to handle my Parameter as a value as it uses the ValueHandlerFactory to retrieve a LongValueHandler. I've been looking into its source code and it is obviously unable to manage with Parameters.

Have i made a mistake here?