How to use 'Hibernate.initialize()'

JCADONG5 · **Joined:** Sun Jan 23, 2011 4:14 am **Posts:** 7

Hi,

I used it as below, but getting an exception when the 'initialize()' method is called (pasted below). Where should I do this 'initialize()'?

Code:

public class TestProductHibernateImpl extends org.springframework.orm.hibernate3.support.HibernateDaoSupport{
.
.
.

   public TestInstance getTestInstance(String instanceId,
         boolean includeTestInstanceQuestions) throws DaoException {
      TestInstance testInstance = (TestInstance) this.getHibernateTemplate()
            .get(TestInstance.class, instanceId);
      if (includeTestInstanceQuestions) {
         this.getHibernateTemplate().initialize(
               testInstance.getInstanceQuestions());
      }
      return testInstance;
   }

Code:

org.springframework.orm.hibernate3.HibernateSystemException: collection is not associated with any session; nested exception is org.hibernate.HibernateException: collection is not associated with any session
   at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:661)
   at org.springframework.orm.hibernate3.HibernateTemplate.initialize(HibernateTemplate.java:651)
   at com.test.product.dataAccess.impl.TestProductHibernateImpl.getTestInstance(TestProductHibernateImpl.java:62)

msj4u · **Joined:** Wed Apr 25, 2007 11:44 pm **Posts:** 59

i haven't used spring with hibernate but the exception that you mentioned is thrown when there is no active connection available in hibernate;

are you closing connection in you classes ?

JCADONG5 · **Joined:** Sun Jan 23, 2011 4:14 am **Posts:** 7

What I am thinking is, I should use HibernateTemplate instead of HibernateDaoSupport, because I need to do the initialize().

Am I correct?

niks23 · **Joined:** Mon Apr 04, 2011 3:31 am **Posts:** 41

ya correct you can do that for example

public interface xyzDao {
Person getxyz(String firstName, String... paths);
}

Here is what an implementation of this DAO may look like:

public class HibernateXyzDao implements xyzDao {

public Person getxyz(String firstName, String... paths) {
Session session = getSession();
Criteria criteriaQuery = session.createCriteria(resultClass);
criteriaQuery.add(Expression.eq("firstName", firstName));
setFetchModes(criteriaQuery, loadedPaths);
for(String eagerPath : paths) {
criteriaQuery.setFetchMode(eagerPath, FetchMode.JOIN);
}
return criteriaQuery.uniqueResult();
}
}

You would use this in your application like this:

XyzDao dao = // get person dao.
dao.getxyz("Jane", "mother", "children", "children.mother");

hope its works

JCADONG5 · **Joined:** Sun Jan 23, 2011 4:14 am **Posts:** 7

niks23 wrote:

ya correct you can do that for example

public interface xyzDao {
Person getxyz(String firstName, String... paths);
}

Here is what an implementation of this DAO may look like:

public class HibernateXyzDao implements xyzDao {

public Person getxyz(String firstName, String... paths) {
Session session = getSession();
Criteria criteriaQuery = session.createCriteria(resultClass);
criteriaQuery.add(Expression.eq("firstName", firstName));
setFetchModes(criteriaQuery, loadedPaths);
for(String eagerPath : paths) {
criteriaQuery.setFetchMode(eagerPath, FetchMode.JOIN);
}
return criteriaQuery.uniqueResult();
}
}

You would use this in your application like this:

XyzDao dao = // get person dao.
dao.getxyz("Jane", "mother", "children", "children.mother");

hope its works

Im afraid you have masked your code too much that it is difficult to understand.

It will be nice of you to repost it, with more complete and clear detail.

For example, what class is xyzDao? Is it a HibernateTemplate or a HibernateDaoSupport?

Please repost with more complete details.

niks23 · **Joined:** Mon Apr 04, 2011 3:31 am **Posts:** 41

Check this ..

http://www.javalobby.org/java/forums/t62077.html