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Forum locked This topic is locked, you cannot edit posts or make further replies.  [ 3 posts ] 
Author Message
 Post subject: Using to List to output query results
PostPosted: Thu Nov 13, 2008 3:06 pm 
Newbie

Joined: Thu Nov 13, 2008 11:37 am
Posts: 3
Hi:

The query string is returning a list which I am trying to display using System.out.println but I am unable to do so. Can someone please help.

I am trying to access the list using the following code, the list size is correct as per the database, I verified it, but how do I get the last name or first name?

I will really appreciate if someone can help. I respect everybody's time and effort

Quote:
I am getting the following error:

Exception in thread "main" java.lang.NullPointerException
at com.nb.siebel.framework.hibernate.HibernateTest.listAccountContact(HibernateTest.java:136)
at com.nb.siebel.framework.hibernate.HibernateTest.main(HibernateTest.java:24)



Hibernate version:3.1

Mapping documents:

Code:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!--
    Mapping file autogenerated by MyEclipse Persistence Tools
-->
<hibernate-mapping>
    <class name="com.nb.siebel.framework.hibernate.Contacts" table="Contacts" schema="dbo" catalog="siebeldb">
        <composite-id name="id" class="com.nb.siebel.framework.hibernate.ContactsId">
            <key-property name="contactId" type="java.lang.Double">
                <column name="ContactID" precision="15" scale="0" />
            </key-property>
            <key-property name="firstName" type="java.lang.String">
                <column name="FirstName" />
            </key-property>
            <key-property name="middleName" type="java.lang.String">
                <column name="MiddleName" />
            </key-property>
            <key-property name="lastName" type="java.lang.String">
                <column name="LastName" />
            </key-property>
        </composite-id>
    </class>
</hibernate-mapping>



Code between sessionFactory.openSession() and session.close():


Code:

      Transaction tx = contactsDAO.getSession().beginTransaction();
      List contact = contactsDAO.findAll();      
      tx.commit();

      System.out.println("List size: " + contact.size());
      //ContactsId localContactsId = new ContactsId();
      for(int i=0;i<contact.size();i++){
         System.out.println(i + ") " + "----------------");
         ContactsId localContacts = (ContactsId)contact.get(i);
         System.out.println(localContacts.getContactId());
      }
      contactsDAO.getSession().close();








Full stack trace of any exception that occurs:

I have provided the error above.



Name and version of the database you are using:

MS SQL Server 2005



The generated SQL (show_sql=true):

13:53:04,171 DEBUG SQL:346 - select contacts0_.ContactID as ContactID2_, contacts0_.FirstName as FirstName2_, contacts0_.MiddleName as MiddleName2_, contacts0_.LastName as LastName2_ from siebeldb.dbo.Contacts contacts0_



DAO Code:
----------------------------------
Code:
   public List findAll() {
      log.debug("finding all Contacts instances");
      try {
         String queryString = "from Contacts";
         Query queryObject = getSession().createQuery(queryString);
         return queryObject.list();
      } catch (RuntimeException re) {
         log.error("find all failed", re);
         throw re;
      }
   }


Contacts.java
----------------------------------

Code:

public class Contacts extends AbstractContacts implements java.io.Serializable {

   // Constructors

   /** default constructor */
   public Contacts() {
   }

   /** full constructor */
   public Contacts(ContactsId id) {
      super(id);
   }

}



AbstractContacts.java
-----------------------------

Code:
public abstract class AbstractContacts implements java.io.Serializable {

   // Fields

   private ContactsId id;

   // Constructors

   /** default constructor */
   public AbstractContacts() {
   }

   /** full constructor */
   public AbstractContacts(ContactsId id) {
      this.id = id;
   }

   // Property accessors

   public ContactsId getId() {
      return this.id;
   }

   public void setId(ContactsId id) {
      this.id = id;
   }

}



ContactsId.java
------------------------
Code:

public class ContactsId extends AbstractContactsId implements
      java.io.Serializable {

   // Constructors

   /** default constructor */
   public ContactsId() {
   }

   /** full constructor */
   public ContactsId(Double contactId, String firstName, String middleName,
         String lastName) {
      super(contactId, firstName, middleName, lastName);
   }

}



AbstractContactsId.java
-----------------------------
Code:

public abstract class AbstractContactsId implements java.io.Serializable {

   // Fields

   private Double contactId;
   private String firstName;
   private String middleName;
   private String lastName;

   // Constructors

   /** default constructor */
   public AbstractContactsId() {
   }

   /** full constructor */
   public AbstractContactsId(Double contactId, String firstName,
         String middleName, String lastName) {
      this.contactId = contactId;
      this.firstName = firstName;
      this.middleName = middleName;
      this.lastName = lastName;
   }

   // Property accessors

   public Double getContactId() {
      return this.contactId;
   }

   public void setContactId(Double contactId) {
      this.contactId = contactId;
   }

   public String getFirstName() {
      return this.firstName;
   }

   public void setFirstName(String firstName) {
      this.firstName = firstName;
   }

   public String getMiddleName() {
      return this.middleName;
   }

   public void setMiddleName(String middleName) {
      this.middleName = middleName;
   }

   public String getLastName() {
      return this.lastName;
   }

   public void setLastName(String lastName) {
      this.lastName = lastName;
   }

   public boolean equals(Object other) {
      if ((this == other))
         return true;
      if ((other == null))
         return false;
      if (!(other instanceof AbstractContactsId))
         return false;
      AbstractContactsId castOther = (AbstractContactsId) other;

      return ((this.getContactId() == castOther.getContactId()) || (this
            .getContactId() != null
            && castOther.getContactId() != null && this.getContactId()
            .equals(castOther.getContactId())))
            && ((this.getFirstName() == castOther.getFirstName()) || (this
                  .getFirstName() != null
                  && castOther.getFirstName() != null && this
                  .getFirstName().equals(castOther.getFirstName())))
            && ((this.getMiddleName() == castOther.getMiddleName()) || (this
                  .getMiddleName() != null
                  && castOther.getMiddleName() != null && this
                  .getMiddleName().equals(castOther.getMiddleName())))
            && ((this.getLastName() == castOther.getLastName()) || (this
                  .getLastName() != null
                  && castOther.getLastName() != null && this
                  .getLastName().equals(castOther.getLastName())));
   }

   public int hashCode() {
      int result = 17;

      result = 37 * result
            + (getContactId() == null ? 0 : this.getContactId().hashCode());
      result = 37 * result
            + (getFirstName() == null ? 0 : this.getFirstName().hashCode());
      result = 37
            * result
            + (getMiddleName() == null ? 0 : this.getMiddleName()
                  .hashCode());
      result = 37 * result
            + (getLastName() == null ? 0 : this.getLastName().hashCode());
      return result;
   }

}



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 Post subject:
PostPosted: Thu Nov 13, 2008 4:11 pm 
Newbie

Joined: Thu Nov 13, 2008 3:25 pm
Posts: 5
Which is the line 136 in HibernateTest.java?


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 Profile  
 
 Post subject:
PostPosted: Fri Nov 14, 2008 11:26 pm 
Newbie

Joined: Thu Nov 13, 2008 11:37 am
Posts: 3
I have resolved this problem, I will mark this as Closed.


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