I'm trying to do a search and i'm getting the following error:
Code:
SEVERE: Servlet.service() for servlet Search threw exception
org.hibernate.QueryException: could not resolve property: name of: com.epixentertainment.model.UserEnt
Here is my call
Code:
public List<UserEnt> searchUsers(String query, String orderProperty, String orderDirection, Long first, Long max){
Criteria criteria = getSession().createCriteria(UserEnt.class);
//match the query in either name or login
criteria.add(Restrictions.or(Restrictions.or(Restrictions.ilike("firstName", query, MatchMode.ANYWHERE),
Restrictions.ilike("lastName", query, MatchMode.ANYWHERE)),
Restrictions.ilike("login", query, MatchMode.ANYWHERE)));
//add the order
if (orderDirection.toLowerCase().equals("asc"))
criteria.addOrder(Order.asc(orderProperty));
else
criteria.addOrder(Order.desc(orderProperty));
//fetch count
criteria.setFirstResult(first.intValue()).setMaxResults(max.intValue());
return criteria.list();
}
and here is my class
Code:
public class UserEnt implements Serializable{
...
/** The first name. */
private String firstName;
/** The last name. */
private String lastName;
/** The login. */
private String login;
...
Seems to be looking for the column named : "name" and rightfully so its not finding it, but why its looking for that and not "firstName" or "lastName" or "login" is not making any sense.
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