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ah
 Post subject: Problem for use an enum for id
PostPosted: Mon Aug 20, 2007 5:32 am 
Newbie

Joined: Mon Aug 20, 2007 5:14 am
Posts: 9
Hibernate version: 3.2.4 sp1

Name and version of the database you are using: Firebird 1.5.3


Hello,

My problem is how use enum for id :

I have this enum :

Code:
public enum Day {
  monday,
  tuesday,
  wednesday,
  thursday,
  friday,
  saturday,
  sunday
}


and this entity :

@Entity
@Table(name="WEEK")
public class Week {

@Id
@Enumerated(EnumType.STRING)
@Column(length=30)
private Day d;

@Column(length=30)
private String truc;

// + getters and setters
}

if I have in Hibernate configuration
<property name="hibernate.hbm2ddl.auto">create</property>
I get this error :
Quote:
GRAVE: Unsuccessful: create table WEEK (d blob not null, truc varchar(30), primary key (d))


If I create myself the table with this sql code :

Code:
create table WEEK (
d varchar(30) not null,
truc varchar(30));

alter table WEEK add constraint C_WEEK primary key(d);

<property name="hibernate.hbm2ddl.auto">update</property>

and I try to persist an Week entity instance, I get this error :



Quote:
Hibernate: insert into WEEK (truc, d) values (?, ?)
20 août 2007 11:27:46 org.hibernate.type.NullableType nullSafeSet
INFO: could not bind value '2c6d8085fef2809ce5f3f3e1e9aee5eef5ede5f2e1f4e9efeeaef3f4f2e9eee7aec4e1f98080808080808080928080f8f2808eeae1f6e1aeece1eee7aec5eef5ed8080808080808080928080f8f0f48086edefeee4e1f9' to parameter: 2; Data truncation
20 août 2007 11:27:46 org.hibernate.util.JDBCExceptionReporter logExceptions
ATTENTION: SQL Error: 0, SQLState: 01004
20 août 2007 11:27:46 org.hibernate.util.JDBCExceptionReporter logExceptions
GRAVE: Data truncation
20 août 2007 11:27:46 org.hibernate.event.def.AbstractFlushingEventListener performExecutions
GRAVE: Could not synchronize database state with session
org.hibernate.exception.GenericJDBCException: could not insert: [essai.enumeration.string.Week]
at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103)
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91)
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2267)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2660)
at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:56)
at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:250)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:234)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
at essai.enumeration.string.WeekDao.create(WeekDao.java:14)
at essai.enumeration.string.Main.main(Main.java:16)
Caused by: java.sql.DataTruncation: Data truncation
at org.firebirdsql.jdbc.field.FBStringField.setBytes(FBStringField.java:341)
at org.firebirdsql.jdbc.AbstractPreparedStatement.setBytes(AbstractPreparedStatement.java:178)
at org.hibernate.type.AbstractBynaryType.set(AbstractBynaryType.java:43)
at org.hibernate.type.SerializableType.set(SerializableType.java:29)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:116)
at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2008)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2243)
... 12 more
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [essai.enumeration.string.Week]
at org.hibernate.exception.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:103)
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:91)
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2267)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2660)
at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:56)
at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:250)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:234)
at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
at essai.enumeration.string.WeekDao.create(WeekDao.java:14)
at essai.enumeration.string.Main.main(Main.java:16)
Caused by: java.sql.DataTruncation: Data truncation
at org.firebirdsql.jdbc.field.FBStringField.setBytes(FBStringField.java:341)
at org.firebirdsql.jdbc.AbstractPreparedStatement.setBytes(AbstractPreparedStatement.java:178)
at org.hibernate.type.AbstractBynaryType.set(AbstractBynaryType.java:43)
at org.hibernate.type.SerializableType.set(SerializableType.java:29)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136)
at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:116)
at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2008)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2243)
... 12 more


It seems that @Enumerated(STRING) is ignored.... I don't understand why.

If anyone have any ideas, thanks you for reply....
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andydale
 Post subject:
PostPosted: Mon Aug 20, 2007 5:40 am 
Senior
Senior

Joined: Tue Jul 25, 2006 9:05 am
Posts: 163
Location: Stuttgart/Karlsruhe, Germany
Hi,

I have no idea why @Enumerated(EnumType.STRING) is not honoured, but as a workaround you could try the following:

Code:
@Id
@Enumerated(EnumType.STRING)
@Column(length=30, columnDefinition="varchar(30)")
private Day d;


Cheers,

Andy

_________________
Rules are only there to be broken

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ah
 Post subject:
PostPosted: Mon Aug 20, 2007 5:52 am 
Newbie

Joined: Mon Aug 20, 2007 5:14 am
Posts: 9
Thanks for this idea, but the result isn't very good:

now Hibernate can create the table Week but the column d is varchar(255) instead of varchar(30), and persist a Week entity instance always made the same error.

It's a very strange problem..
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ah
 Post subject:
PostPosted: Mon Aug 20, 2007 8:20 am 
Newbie

Joined: Mon Aug 20, 2007 5:14 am
Posts: 9
After search in Sun J2EE doc, I found this doc http://java.sun.com/xml/ns/persistence/orm_1_0.xsd.
It seems that Enumerated couldn't be combined with Id but only with Basic ...

I'm afraid there isn't solution for my problem...
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emmanuel
 Post subject:
PostPosted: Fri Aug 24, 2007 10:22 pm 
Hibernate Team
Hibernate Team

Joined: Sun Sep 14, 2003 3:54 am
Posts: 7256
Location: Paris, France
I guess by using a composite id, you could make it work. I haven't tried though

_________________
Emmanuel

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stuarty-boarder
 Post subject:
PostPosted: Tue Oct 16, 2007 4:41 am 
Newbie

Joined: Wed Sep 26, 2007 6:09 am
Posts: 3
I ran into the same problem and tried as Emmanuel suggested. I effectively wrapped the enum field in a primary key class and can now store it using either ORDINAL or STRING by setting the Enumerated annotation on the field within the primary key class.
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cameronbraid
 Post subject:
PostPosted: Sat Mar 01, 2008 12:42 pm 
Beginner
Beginner

Joined: Thu Aug 26, 2004 5:53 am
Posts: 37
I ran into the same problem.

Still working on a solution.

Any chance that hibernate could support this combination ?
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cameronbraid
 Post subject:
PostPosted: Sat Mar 01, 2008 1:28 pm 
Beginner
Beginner

Joined: Thu Aug 26, 2004 5:53 am
Posts: 37
this seems to do the trick.

Code:
   @Id
   @Type(type="org.hibernate.type.EnumType",parameters={
      @Parameter(name="enumClass", value="your.enum.package.CountryCode")
   })   
   @Column(length=2, columnDefinition="char(2)")
   private CountryCode code;
   public CountryCode getCode() {
      return code;
   }
   public void setCode(CountryCode code) {
      this.code = code;
   }


It may be good if hibernate could just support the @Enumerated annotation for this case, since it is really just a shorthand for the above @Type definition
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cameronbraid
 Post subject:
PostPosted: Sun Mar 02, 2008 1:21 pm 
Beginner
Beginner

Joined: Thu Aug 26, 2004 5:53 am
Posts: 37
Note also that for String enums you need this parameter

Code:
@Parameter(name="type", value="1") // 1=char, 12 = varchar
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