Do not initialize proxy when calling my overriden hashCode

ge0ffrey · **Joined:** Thu Oct 13, 2005 4:19 am **Posts:** 98

I've implemented a custom hashCode (and equals) method based on the id of my persistent object.
This hashCode method works, even if it's a proxy.

Code:

    @Override
    public int hashCode()
    {
        // getClass() is not hashbaar
        return new HashCodeBuilder()
                .append(getId())
                .toHashCode();
    }

    @Override
    public boolean equals(Object o)
    {
        if (this == o)
        {
            return true;
        }
        if (o instanceof JpaIdentifiable)
        {
            JpaIdentifiable other = (JpaIdentifiable) o;
            if (getId() == null || other.getId() == null)
            {
                return false;
            }
            return getId().equals(other.getId())
                    && isSameClassIgnoringProxySubclass(other);
        } else {
            return false;
        }
    }

The problem is, that hibernate insists on intializing this object anyway when hashCode() is called. At that point it's detached in my swing client and I get a LazyInitializationException of course.

From the hibernate manual:

Code:

 Certain operations do not require proxy initialization

    *

      equals(), if the persistent class does not override equals()
    *

      hashCode(), if the persistent class does not override hashCode()
    *

      The identifier getter method 

Hibernate will detect persistent classes that override equals() or hashCode(). 

Can I tell hibernate "yes I 've overridden the hashCode() method, but I still don't want you to require proxy initialization for it"?

Thanks for any and all help :)