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Hibernate version:
3

Mapping documents:

<hibernate-mapping>
<typedef name="WebsiteType" class="emst.persistence.GenericEnumUserType">
<param name="enumClass">emst.website.WebsiteType</param>
</typedef>

<class name="emst.dao.command.CommandObject" abstract="true">
<id name="coId" column="coId" type="long">
<generator class="uuid"/>
</id>

<union-subclass name="emst.dao.command.objects.CommandActionTrigger" table="CO_CommandActionTrigger">
<property name="note"/>
<property name="command"/>
</union-subclass>

.......
</hibernate-mapping>

I have an interface, and i've implemented all the subclasses as union-subclass I was wondering if there is a way to have an id that's only in the database. I don't want to have to add a getter and setter in every class that implements the interface.

any help would be appreciated, thanks.
Joe

Have you considered using an abstract class instead of an interface?

You can have the abstract class implement the getter and setter for id.