Hello,

I have a problem in reverse engineering with 3.2.0beta9a. A hibernate.reveng.xml file with a "key-column" like this:

<key-column name="IDCONTA" type="integer"/>

generates, Java code:

private Integer idconta; //wrapper type

and hbm.xml file with:

<id name="idconta" type="integer">

but, when i switch de type to "long" the behavior is diferent:

<key-column name="IDCONTA" type="long"/>

generates, Java code:

private long idconta; //primitive type

and hbm.xml file with:

<id name="idconta" type="long">

There's a way to choose between primitive and wrapper types? This behavior is not homogeneous.

Thanks for your response and suggestions.

if you want the primitive type then use the "int" name; not "integer" nor "java.lang.Integer"

How to get Long (wrapper) in Java and "long" type in hbm?

I use this code in hibernate.reveng.xml and it don't work.

<key-column name="IDCONTA" type="Long"/>

java.lang.Long

If I use "int" name, hbm is generated with "int" as a Hibernate type. "int" is not a Hibernate type.

Thanks for the response Max. But i still have problems... If a use "java.lang.Long" a get this hbm:

<id name="idconta" type="java.lang.Long">

Seems wrong to me.

make a choice - either you want primitives or you want wrappers....

How should hbm2java know that when you use "long" you want it to be "java.lang.Long" ? It would require more options/settings so it is much simpler to just say "if you want long then write long, if you want java.lang.Long then write java.lang.Long" .....and that is what the tooling does.

for hibernate internally there are no difference between long and java.lang.Long so it does not affect the core mechanics at all.

oh and if you really want an option for it you can do




...see *that* looks wrong! :)

Thanks Max. I didn't knew that Hibernate mapping supports Java types in "hibernate type" properties. I use java.lang.Long or java.lang.Integer and that works.