logging returned objects prints out [Ljava.lang.Object;@6179

BusyByte · **Joined:** Sun Feb 12, 2006 12:19 am **Posts:** 20

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Hibernate version:
3.1

Code between sessionFactory.openSession() and session.close():
ArrayList<ReleaseScheduleBean> list = (ArrayList<ReleaseScheduleBean>)this.getHibernateTemplate().find("from " + ReleaseScheduleBean.class.getName() + " as rsBean inner join rsBean.milestone as msBean where msBean.productID = ? order by msBean.number" , id);

if(logger.isDebugEnabled())
{
for(int i = 0; list != null && i < list.size(); ++i)
{
logger.debug("ReleaseScheduleDAO list[" + String.valueOf(i) + "]:" + String.valueOf(list.get(i)));
}
}

Log output:

ReleaseScheduleDAO list[0]:[Ljava.lang.Object;@12f195
ReleaseScheduleDAO list[0]:[Ljava.lang.Object;@12f195
ReleaseScheduleDAO list[1]:[Ljava.lang.Object;@1b29f80
ReleaseScheduleDAO list[1]:[Ljava.lang.Object;@1b29f80
ReleaseScheduleDAO list[2]:[Ljava.lang.Object;@5b24c
ReleaseScheduleDAO list[2]:[Ljava.lang.Object;@5b24c
ReleaseScheduleDAO list[3]:[Ljava.lang.Object;@1fcd402
ReleaseScheduleDAO list[3]:[Ljava.lang.Object;@1fcd402
ReleaseScheduleDAO list[4]:[Ljava.lang.Object;@1c2ec05
ReleaseScheduleDAO list[4]:[Ljava.lang.Object;@1c2ec05
ReleaseScheduleDAO list[5]:[Ljava.lang.Object;@1558dc
ReleaseScheduleDAO list[5]:[Ljava.lang.Object;@1558dc
ReleaseScheduleDAO list[6]:[Ljava.lang.Object;@17d03c5
ReleaseScheduleDAO list[6]:[Ljava.lang.Object;@17d03c5
ReleaseScheduleDAO list[7]:[Ljava.lang.Object;@82a13a
ReleaseScheduleDAO list[7]:[Ljava.lang.Object;@82a13a
ReleaseScheduleDAO list[8]:[Ljava.lang.Object;@2726b2
ReleaseScheduleDAO list[8]:[Ljava.lang.Object;@2726b2
ReleaseScheduleDAO list[9]:[Ljava.lang.Object;@5da37c
ReleaseScheduleDAO list[9]:[Ljava.lang.Object;@5da37c
ReleaseScheduleDAO list[10]:[Ljava.lang.Object;@19845fb
ReleaseScheduleDAO list[10]:[Ljava.lang.Object;@19845fb
ReleaseScheduleDAO list[11]:[Ljava.lang.Object;@1a791f
ReleaseScheduleDAO list[11]:[Ljava.lang.Object;@1a791f
ReleaseScheduleDAO list[12]:[Ljava.lang.Object;@6179e
ReleaseScheduleDAO list[12]:[Ljava.lang.Object;@6179e

Name and version of the database you are using:
MySQL 4

I have an overloaded toString method so I don't understand why it's printing out [Ljava.lang.Object;@6179e instead of calling the objects toString method

Any Help?

max · **Posted:** Sat Sep 16, 2006 11:57 am

because each element is apparently an array.

BusyByte · **Joined:** Sun Feb 12, 2006 12:19 am **Posts:** 20

How come I'm getting an array of objects looks like I get two of the same ReleaseScheduleBean and then two of the MilestoneBean? Here is my query:

Code:

this.getHibernateTemplate().find("from " + ReleaseScheduleBean.class.getName() + " rsBean inner join rsBean.milestone msBean where msBean.productID = ? order by msBean.number" , id);

I'm expecting an ArrayList of ReleaseScheduleBeans with it's milestone property set with the joined MilestoneBean value.

Here's my mappings:

Code:

<hibernate-mapping>
   <class name="com.age.j.soft.hibernate.ReleaseScheduleBean" table="release_schedule">
      <id name="releaseScheduleID" column="release_schedule_id">
         <generator class="native" />
      </id>
      <many-to-one name="milestone" column="milestone_id" class="com.age.j.soft.hibernate.MilestoneBean" not-null="true"/>
      <!--  <property name="milestoneID" column="milestone_id"/> -->
      <property name="feature" column="feature"/>
   </class>
</hibernate-mapping>

<hibernate-mapping>
   <class name="com.age.j.soft.hibernate.MilestoneBean" table="milestone">
      <id name="milestoneID" column="milestone_id">
         <generator class="native" />
      </id>
      <property name="productID" column="product_id"/>
      <property name="tentativeDate" column="tentative_date" type="date"/>
      <property name="number" column="number"/>
      <property name="releaseDate" column="release_date" type="date"/>
      <property name="maxVersion" column="max_version"/>
      <property name="minVersion" column="min_version"/>
   </class>
</hibernate-mapping>

Here's my objects:

Code:

public class ReleaseScheduleBean implements Serializable{
   protected Integer releaseScheduleID = null;
   
   protected MilestoneBean milestone = null;
   
   //protected Integer milestoneID = null;
   
   protected String feature = null;
...

public class MilestoneBean implements Serializable{
   
   protected Integer milestoneID = null;
   
   protected Integer productID = null;

   protected Integer number = null;
   
   protected Date tentativeDate = null;

   //nullables
   
   protected Date releaseDate = null;

   protected Integer maxVersion = null;

   protected Integer minVersion = null;

...

Can you help me?

christian · **Posted:** Sun Sep 17, 2006 3:08 am

SELECT foo from Foo, Bar

BusyByte · **Joined:** Sun Feb 12, 2006 12:19 am **Posts:** 20

I don't have to do any joins either in the query or the mapping file?

BusyByte · **Joined:** Sun Feb 12, 2006 12:19 am **Posts:** 20

I got it but I had to put lazy="false" on the following mapping:

<many-to-one lazy="false" name="milestone" column="milestone_id" class="com.age.j.soft.hibernate.MilestoneBean" unique="true" not-null="true"/>

I don't understand why I was getting a lazy exception without it?

Can somebody explain?

Shawn