Here is my code
Code:
public class VarCharString implements UserType, ParameterizedType {
private int length;
public void setParameterValues(Properties parameters) {
length = Integer.parseInt(parameters.getProperty("length"));
}
...............
}
and here is my mappings
Code:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<typedef name="FirstName"
class="default.VarCharString">
<param name="length">30</param>
</typedef>
<!-- rename class to student card -->
<class name="default.Student" table="studentcard" schema="public" lazy="false">
<property name="firstname" type="FirstName">
<column name="firstname" length="30" />
</property>
<property name="middlename" type="string">
<column name="middlename" length="40" />
</property>
<property name="lastname" type="string">
<column name="lastname" length="50" />
</property>
</class>
</hibernate-mapping>
The question is: should I define
Code:
<typedef name="MiddleName"
class="default.VarCharString">
<param name="length">40</param>
</typedef>
and
Code:
<typedef name="LastName"
class="default.VarCharString">
<param name="length">50</param>
</typedef>
or there is a way to force ParameterizedType.setParameterValues() to "read" length param from here
Code:
<property name="firstname" type="FirstName">
<column name="firstname" length="30" />
</property>
maybe there are some other ways to slove this problem?
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