I need to habe long types (fully qualified classname) instead of short-name.
How can I control this?
Specifiy it in cfg.xml?

huh ?

I need not type="long"

I need type="java.lang.Long"

Also, I need to have a custom type-mapping:
oracle:number should map to java.lang.Double, not to BigDecimal

What is best practise to specify this?

in reveng.xml

what I see from the docs is

<type-mapping>
<sql-type jdbc-type="VARCHAR" length='20' hibernate-type="SomeUserType" /> <!-- jdbc-type is name fom java.sql.Types -->
<sql-type jdbc-type="VARCHAR" length='1' hibernate-type="yes_no" />
<sql-type jdbc-type="NUMERIC" precision='1' hibernate-type="boolean" /> <!-- length, scale and precision can be used to specify the mapping precisly -->
<sql-type jdbc-type="NUMERIC" hibernate-type="long" /> <!-- the type-mappings are ordered. This mapping will be consulted last, thus overriden by the previous one if precision=1 for the column -->
</type-mapping>

is there a DTD for this, perhaps even documented?
I can't see any way here to specify long types (fully qualified class names).

hibernate-type="java.lang.Long" ? that is how you normally do it.

and yes there is a dtd for it - hibernate-reverseengineering.dtd

ah great - I think you added it just now.

err - somehow it won't work. what's wrong in this config:

<type-mapping>
<sql-type jdbc-type="NUMERIC" length="8" scale="2" hibernate-type="java.lang.Long" />
</type-mapping>

error appears:

org.hibernate.MappingException:Could not configure overrides from file: ... reveng.xml

look in your stacktrace - it will state what part of the xml it doesnt like ...