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Forum locked This topic is locked, you cannot edit posts or make further replies.  [ 3 posts ] 
Author Message
 Post subject: ... order by?
PostPosted: Tue Apr 27, 2004 6:17 am 
Beginner
Beginner

Joined: Tue Jan 27, 2004 8:25 am
Posts: 45
Hi all!
I'm trying to create an HQL query, and order it, but I'm having some trouble, due to subclasses I guess.

This is my mapping:
Code:
<class name="ParsysUser" discriminator-value="U">
    <id name="code" type="long" column="code" unsaved-value="null">
      <generator class="native" />
    </id>
    <discriminator column="type" type="character" />   
    <property name="name" type="string" />
    <property name="password" type="string" />

    <subclass name="RemoteSystem"
       discriminator-value="R" dynamic-update="true"
       dynamic-insert="true">
    </subclass>
    <subclass name="CentralOperator"
       discriminator-value="C" dynamic-update="true"
       dynamic-insert="true">
       <many-to-one name="personalInfo" class="Person" column="personalInfo"/>
    </subclass>
    <subclass name="AgencyOperator"
       discriminator-value="A" dynamic-update="true"
       dynamic-insert="true">
       <many-to-one name="personalInfo" class="Person" column="personalInfo"/>
       <many-to-one name="branchOffice" class="BranchOffice" column="branchOffice"/>
    </subclass>
    <subclass name="es.parsec.parsys.user.Supplier"
       discriminator-value="S" dynamic-update="true"
       dynamic-insert="true">
       <many-to-one name="personalInfo" class="Person" column="personalInfo"/>
    </subclass>
    <subclass name="es.parsec.parsys.user.Visitor"
       discriminator-value="V" dynamic-update="true"
       dynamic-insert="true">
    </subclass>
   
</class>


<class name="Person">
    <id name="code" type="long" column="code" unsaved-value="null">
      <generator class="native" />
    </id>
    <property name="firstName" type="string" />
    <property name="middleName" type="string" />
    <property name="lastName" type="string" />
</class>


And this are my classes regardind the problem....

Code:

public class ParsysUser implements Principal
{
   public static String REMOTE_SYSTEM = "R";
   public static String CENTRAL_OPERATOR = "C";
   public static String AGENCY_OPERATOR = "A";
   public static String SUPPLIER = "S";
   public static String VISITOR = "V";
   
   private Long code;
   private String name;
   private String password;
   private String type;

// follows setters and getters...
}

public class AgencyOperator extends ParsysUser
{
   private Person personalInfo;
   private BranchOffice branchOffice;
// follows setters and getters...
}


public class Person {
   
    private Long code;
   private String firstName;
   private String middleName;
   private String lastName;

// follows getters and setters
}


So, what Im trying to do is to get all the users from my database, who are AgencyOperators, order by their personalInfo's FirstName...
This is the error and the query:

Code:
net.sf.hibernate.QueryException: could not resolve property type: personalInfo [from ParsysUser as age where age.class = AgencyOperator  order by age.personalInfo.firstName asc]


How should I implement the query? Can anyone help me?
Thanks in advance!


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 Post subject:
PostPosted: Tue Apr 27, 2004 9:19 am 
Hibernate Team
Hibernate Team

Joined: Tue Sep 09, 2003 2:10 pm
Posts: 3246
Location: Passau, Germany
do a "from AgencyOperators ..." instead.


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 Post subject:
PostPosted: Tue Apr 27, 2004 10:50 am 
Beginner
Beginner

Joined: Tue Jan 27, 2004 8:25 am
Posts: 45
michael wrote:
do a "from AgencyOperators ..." instead.


that worked!
thank you very much!!!


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