USE THE FOLLOWING WAY, IT WILL WORK-----------------------------------------
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="contact.Picture" table="PICTURE">
<id name="id" type="integer" column="ID" >
<generator class="assigned"/>
</id>
<property name="image" column="IMAGE" type="java.sql.Blob"/>
</class>
</hibernate-mapping>
-------------------------------------------
package contact;
import java.util.*;
import java.sql.Blob;
public class Picture{
private int id;
private Blob image;
public Blob getImage() {
return this.image;
}
public void setImage(Blob image) {
this.image = image;
}
/**
* @return ID Returns ID
*/
public int getId() {
return id;
}
/**
* @param l Sets the ID
*/
public void setId(int l) {
id = l;
}
}
----------------------------------------
package contact;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;
import org.hibernate.Transaction;
import org.hibernate.Hibernate;
import java.io.*;
import java.util.*;
import java.sql.Blob;
public class First_Insert_Blob {
public static void main(String[] args) {
Session session = null;
FileInputStream fs=null;
File file=null;
try{
file = new File("D:\\xyz.gif");
fs = new FileInputStream(file);
Blob photo=Hibernate.createBlob(fs);
SessionFactory sessionFactory = new
Configuration().configure().buildSessionFactory();
session =sessionFactory.openSession();
Transaction tx = session.beginTransaction();
System.out.println("Inserting Record");
Picture picture = new Picture();
picture.setId(2);
picture.setImage(photo);
session.save(picture);
tx.commit();
System.out.println("Done");
}catch(Exception e){
System.out.println(e.getMessage());
}finally{
// Actual contact insertion will happen at this step
session.flush();
session.close();
}
}
}
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