I would like to translate the annotations of this portion of code in hbm

public abstract class myObject<E extends Enum>
{

@Enumerated(EnumType.STRING)
@Column(length = 30)
@Length(min = 1, max = 30)
@NotNull
private E myField;

...

}

I have try this:

<property name="myfield" length="30">
<type name="org.hibernate.type.EnumType">
<param name="enumClass">java.lang.Enum</param>
</type>
</property>

but I get an error...

Does anyone have a solution for this ?

Thanks in advance,
tiggy

E needs to be resolved to a specific type, not java.lang.Enum

I've been seacrhing for a way to map enums to varchar columns for a long time usinh .hbm files. This post gave me the clue I needed, so for everyone looking for this solution. This is how you modify the mapping above to map to varchars:

<property name="myfield" length="30">
<type name="org.hibernate.type.EnumType">
<param name="enumClass">org.judge.myenum</param>
<param name="type">12</param>
</type>
</property>

The number 12 is one of the constants from java.sql.Types.

Can anyone provide a good explanation regarding the usage of EnumType: The parameters needed and their meaning. For example: Why hardcoding 12?

I couldn't any good explanation while Googling.

Asaf

As said above, this is the constant value in java.sql.Types. Ain't gonna change

And how to do it for a java.util.Map where enum is the key(index)?

Regards

I would also like to know how to save maps in Hibernate where the key is an enum, doing this with a .hbm file, not with annotations.

Cheers,
Stef