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pala00
 Post subject: Discriminator type with annotations
PostPosted: Sun Mar 02, 2008 4:01 pm 
Newbie

Joined: Sun Mar 02, 2008 3:43 pm
Posts: 9
Hello,

I'm new to hibernate, and trying to port my home-made application to hibernate.

I'm a willing to use an userType as a discriminator.

I have written an EnhancedUserType for this and succeed to use it with hibernate xml.

My problem is that I wanted to use annotations and I can't figure out how to specify the discriminator type.

discriminationType in @DiscriminationColumn seem to take only a enum value and not a type name.

Is there an annotation I'm missing ?
am I forced to use xml notation ?
is there a way to add my own annotations?
Is there a way to mix xml notations with annotations? Apparently I can't figure out this configuration un JPA xml either.


See below for working xml config file. The discriminator returns a string with fully qualified classpath.

Any help welcome :)


Code:
<hibernate-mapping package="com.dg.sim.backend.operationlog" default-access="field">
   <typedef name="com.dg.sim.backend.operations.Operation.Discriminator"
      class="com.dg.persistence.hibernate.userType.ObjectDiscriminatorUserType">
      <param name="class">com.dg.sim.backend.operations.Operation</param>
   </typedef>
  <class name="OperationLog" table="operation_log" discriminator-value="PERSO">
        
        <id name="id" type="com.dg.persistence.hibernate.userType.BasicIndexUserType"/>
        <discriminator formula="Op_Id" type="com.dg.sim.backend.operations.Operation.Discriminator"/>
        <!--  <discriminator column="DTYPE" type="string"/>-->
        <property name="jId" column="J_id" type="com.dg.persistence.hibernate.userType.BasicIndexUserType"/>
        <property name="operation" column="Op_Id">
           <type name="com.dg.persistence.hibernate.userType.ObjectUserType">
              <param name="class">com.dg.sim.backend.operations.Operation</param>
           </type>
        </property>
        <many-to-one name="joueur" column="J_id" not-null="true" class="com.dg.sim.backend.Joueur" insert="false"
        update="false"/>
        <property name="date"/>
        <property name="realdate"/>
        <property name="oldKarma" column="oldkarma"/>
        <property name="karma"/>
        <property name="newKarma" column="newkarma"/>
        <property name="status"/>
        <property name="log"/>
        <property name="freeString"/>
        <subclass name="OperationTest">
              <property name="karm" column="val1"/>
        </subclass>
        <subclass name="OperationPersoLog">
              <property name="persoId" column="idx1" type="com.dg.persistence.hibernate.userType.BasicIndexUserType"/>
              <property name="argent" column="money1" type="com.dg.persistence.hibernate.userType.MoneyUserType"/>
              <property name="moral" column="val1" />
              <property name="stress" column="val2"/>
              <property name="social" column="val3"/>
              <property name="argentN" column="n_money1" type="com.dg.persistence.hibernate.userType.MoneyUserType"/>
              <property name="moralN" column="n_val1"/>
              <property name="stressN" column="n_val2"/>
              <property name="socialN" column="n_val3"/>            
        </subclass>
  </class>
</hibernate-mapping>
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pala00
 Post subject:
PostPosted: Mon Mar 03, 2008 4:09 pm 
Newbie

Joined: Sun Mar 02, 2008 3:43 pm
Posts: 9
Nobody knows?

I've gone through hibernate source as far as I can understand it, it can't be done with annotations.
I still have to look for JPA xml files.

I'm stuck with 3 options:
1)use hibernate xml format.
2)don't use usertype discriminator
3)add a personal annotation.

for 3) I imagine something like this:

get all persistent classes from configuration and iterate them. If they have a discriminator, look for my own annotation and add it to the discriminator.
Seems feasible to me.

am I missing something obvious ?
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pala00
 Post subject:
PostPosted: Mon Mar 03, 2008 10:45 pm 
Newbie

Joined: Sun Mar 02, 2008 3:43 pm
Posts: 9
I worked on 3) and I got to something apparently working.

I'm still a little bit worried, I worked my way by reading more code than documentation, So I'm not quite sure it is a nice way to do it or a bad hack
that would break with next version.

I am also still wondering if there isn't any other way to implement discriminatorType with annotations.



I past the code there in case it is any use to someone. (although I mean to be speaking to myself here)




Attention: you need to use cfg.buildEntityManagerFactory() after that
and nor Persistence.createEntityManagerFactory() otherwise you'll work with another Factory.


Code:
      org.hibernate.ejb.Ejb3Configuration cfg=new org.hibernate.ejb.Ejb3Configuration();
      cfg.configure("myconf",null);
      debug(ConfigurationEnhancer.class," configure done ");
      Mappings mappings=cfg.getHibernateConfiguration().createMappings();
      for(Iterator it=cfg.getClassMappings();it.hasNext();){         
         PersistentClass classe=(PersistentClass) it.next();
         debug(ConfigurationEnhancer.class,"checking ",classe," for Discrimator");
         SimpleValue value=(SimpleValue)classe.getDiscriminator();
         if(value!=null){
            String name=classe.getClassName();
            try{
               debug(ConfigurationEnhancer.class,"checking ",name," for user DiscrimatorType");
               Class maClasse=Class.forName(name);
               if(maClasse.isAnnotationPresent(DiscriminatorType.class)){
                  DiscriminatorType type=(DiscriminatorType) maClasse.getAnnotation(DiscriminatorType.class);
                  String typeName=type.type();
                  debug(ConfigurationEnhancer.class,"annotation present in",name,"type",typeName);
                  TypeDef typeDef=mappings.getTypeDef(typeName);
                  if(typeDef!=null){
                     debug(ConfigurationEnhancer.class,"typedef found for",typeName);
                     typeName=typeDef.getTypeClass();
                     // parameters on the property mapping should
                     // override parameters in the typedef
                     Properties parameters = new Properties();
                     parameters.putAll( typeDef.getParameters() );
                     if ( !parameters.isEmpty() ) value.setTypeParameters( parameters );      
                  }
                  debug(ConfigurationEnhancer.class,"set type",typeName);
                  if ( typeName != null ) value.setTypeName( typeName );
               }
            }
            catch(ClassNotFoundException e){
               staticError(ConfigurationEnhancer.class,e);
            }
         }
      }
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pala00
 Post subject:
PostPosted: Tue Mar 04, 2008 4:53 pm 
Newbie

Joined: Sun Mar 02, 2008 3:43 pm
Posts: 9
Apparently my patch works but bug if Tomcat have a Session.ser on but.
It must do some kind of deserialization that would block my hack in some way.

I'd really like some help for some right way to do that.
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