Hi Guys

I created a view with three columns and also implemented a model class for that. The view doens't have an id(pk) column and therefore I didn't define any @hibernate.id in my model class.
But as soon as I compile it with the xdoclet it come back with the following error: ... misses ID property....

Is there a way to develop a model class without the hibernate.id property in xdoclets ?

DB:Oracle
Hibernate 3.0

Hibernate requires the ID. Its not a relational entity if you do not have something acting as the key. Some people make all fields the properties of one large composite key, others choose the fields that can be a unique indentifier, other options (limited though) is the rowid. First decide how you want to do it with hibernate then look at getting XDoclet to generate the mapping approach that you have chosen.

That would suit me. How do I do this ? Is there a @hibernate.composite-id tag ?

Cheers
Rolf

See http://xdoclet.sourceforge.net/xdoclet/tags/hibernate-tags.html

for a list of tags (for the latest XDoclet release).

As far as using it, you need to setup the main class with an ID reference and then all the properties of the class that is the key will be tagged appropriatey.

XDoclet does not support integrated composite keys.
Search this forum for other posts on composite keys and XDoclet for more info (or Google).

Is there any sample code for composite keys available ?

Some more support for integrated comnposite Keys is in CVS now. You could also use a inner class as the key rather than a full class. In anycase, there are sample with the XDoclet distribution/CVS.

See JIRA for latest enhancements
http://opensource2.atlassian.com/projects/xdoclet/browse/XDT-414

I decided to have a quick look around and found this good tutorial (Hibernate 2 and XDoclet) that also includes composite keys.

http://www.downside.ch/hibernate/hibernatetutorial-1.4.pdf

Hope this helps.