I am using JPA with Hibernate to create a Java SE desktop application. We have historically used an eight character identifier to uniquely identify a database area. Users can create new database areas which is assigned an identifier. I need to have a persistence unit created using this identifier. I don't know how to create a new persistence unit using this identifier after the application has been deployed. Any assistance that can be provided would be greatly appreciated. Dan

Well, as it turns out the answer to my question was much easier than I could have ever imagined. I was wondering why no one else seemed to have this problem. So, all I had to do was pass the 8 character studyId to the class that creates the EntityManagerFactory. I used the Persistence.createEntityManagerFactory(String persistenceUnit, Map<String, String> properties) to provide the "hibernate.connection.url" property a value of "jdbc:derby://localhost/database/EditorDatabase/"+studyId+";create=true";
Where the studyId represents the 8 character Id that the user selects when deciding which database to edit. It works like a charm.