Hibernate version: 3.2.6.ga

I have two classes, A and B.


Mapped as following:

In A.hbm.mxl

<set name="b" lazy="true">
<key column="b_fk"/>
<one-to-many class="B"/>
</set>

In B.hbm.xml:

<many-to-one name="a" class="A" column="b_fk">
</many-to-one>

I have a hql query:

Select a
From A a inner join a.B b
where b.(lots of trivial conditions on 'b').

This gives me a list of A's in my dao. However, as the relationship bertween A and B is lazy; B is not initialised.

I can't iterate through the list and use Hibernate.initialise as this would ignore the conditions in the hql.
I know I could change the hql and get it to bring back on Object[] containing A and B but I wanted to get the B's through a.getB();

In my Dao:



Is there a way to initialise the B's from inside the hql, whilst still bringing only a List of A's back?

hi,
first of all I guess you should use MappedBy for manytoone relation - that will force hibernate to resolve that relation according to the first one. It should be done like that for bidirectional relations.

I use annotations but the example below should help you anyway:

class A
@OneToMany(mappedBy= "a_prop" ),
private Set<B> listofBs ;

class B
@ManyToOne
@JoinColumn(name = "a_id")
A a_prop;

It means that Set in class A is populated according to property a_prop in class B

I hope it helps

Hi, thanks for the response.

I can't see the equivalent to "mappedBy" using mapping files. How do I do it?