Hi,

I am using JSF, Spring and Hibernate with mysql as my db.

I want to save pcode and pname,etc in the db.

I used getHibernateTemplate.save(obj);

I am facing an issue like when i add the same pcode and pname which is existing.... It is throwing Error : BatchUpdateException

Caused by: java.sql.BatchUpdateException: Duplicate entry 'T1-test1' for key 1

I am unable to handle or catch this exception.

<code>
public PartnerMast save(PartnerMast entity) {
try{
System.out.println("Calling Save Method.............");
entity.setIsActive("Y");
getHibernateTemplate().save(entity);
System.out.println("Record Saved..............");
}catch(Exception e){
System.out.println("Excep :"+e);
}
</code>
I am not able to catch
~~~~~~~~~~~~~~~~~~~~~
catch(BatchUpdateException e)
~~~~~~~~~~~~~~~~~~~~~

The thing is i want to catch this exception and display the msg n jsf ui.

Could anyone pls help me could i handle this exception.

Thanks,
Ambika☺

I don't think there is a way to tweak the hibernate, unless you would change it's code a lot. You will probrably need to do something like this:



Regards,
Pavol