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How to configure the session factory dynamically ?

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prabhu_d

Post subject: How to configure the session factory dynamically ?

Posted: Wed Jul 25, 2007 6:30 am

Newbie

Joined: Wed Jul 25, 2007 6:14 am
Posts: 3

Hi All,

Our web application runs on 57 different places (57 session factories and data sources) . Based on the url, my filter class will find which session factory and data source name to use.

My question is how to override or set the value of the session factory and data source name dynamically to the hibernate.cfg.xml file (I will know the value only after the user entered the url) ?

Is there any alternative way to implement this?

Thanks in advance,

Regards,
Prabhu.

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amila733

Post subject:

Posted: Wed Jul 25, 2007 7:23 am

Senior

Joined: Thu May 17, 2007 2:31 am
Posts: 194
Location: Sri Lanka

Hi

use this code in your Application to initialize new sessionfactory by user given parameters. remove cfg.xml

Code:

Configuration confg = new Configuration();
        
        confg.setProperty("hibernate.connection.driver_class","net.sourceforge.jtds.jdbc.Driver");
        confg.setProperty("hibernate.connection.url","jdbc:jtds:sqlserver://"+servername+":" +hibernateConfig.getPort()  +"/" + dbname);
        confg.setProperty("hibernate.connection.username",username);
        confg.setProperty("hibernate.connection.password",password);        
        confg.setProperty("hibernate.dialect","org.hibernate.dialect.SQLServerDialect");
        confg.setProperty("hibernate.connection.pool_size",""+poolsize);
        //confg.setProperty("hibernate.cache.provider_class","org.hibernate.cache.NoCacheProvider");
        confg.setProperty("hibernate.cache.provider_class","org.hibernate.cache.OSCacheProvider");
                
        
        confg.setProperty("hibernate.current_session_context_class","thread");
        
        confg.setProperty("hibernate.jdbc.use_scrollable_resultset","true");
        confg.setProperty("hibernate.show_sql","true");
        
        

        
        
        try{
              

            confg.addClass(Class2.class); 
            confg.addClass(Class2.class);

sessionFactory = confg.buildSessionFactory();

} catch (MappingException e) {
                       throw e;
        } catch (HibernateException e) {
           throw e;

        }

Amila
(Don't forget to rate if helps)

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prabhu_d

Post subject:

Posted: Wed Jul 25, 2007 7:54 am

Newbie

Joined: Wed Jul 25, 2007 6:14 am
Posts: 3

Hi Amila,

Thanks for your quick reply. I didn't remove the hibernate.cfg.xml file. I removed only the below tag

<property name="hibernate.connection.datasource">java:/eDataSource</property>

and added the same using set property

Configuration confg = new Configuration();
confg.setProperty("hibernate.connection.datasource","java:/eDataSource");

sessionFactory =confg.configure().buildSessionFactory();

It works fine. But how do I set the session factory name dynamically?

I need to replace or add the value of this <session-factory .. > tag

<session-factory name="java:/hibernate/EHibernateFactory">
....
</session-factory>

How to do add or replace the value of the session factory dynamically?

Regards,
Prabhu

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amila733

Post subject:

Posted: Wed Jul 25, 2007 8:05 am

Senior

Joined: Thu May 17, 2007 2:31 am
Posts: 194
Location: Sri Lanka

Hi

use SessionFactoryObjectFactory.addInstance() method to add your dynamically created sessionFactory to JNDI lookups

Amila

(Don't forget to rate if helps)

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prabhu_d

Post subject:

Posted: Wed Jul 25, 2007 8:10 am

Newbie

Joined: Wed Jul 25, 2007 6:14 am
Posts: 3

Hi Amila,

I got the attribute name (hibernate.session_factory_name) to configure session factory dynamically.

It works fine.

Thanks a lot. You gave me a good hint.

Regards,
Prabhu.

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