Hello!
I need to persist an array of String, which can contain null values. I expected that loaded array would be same as persised, but Hibernate doesn't save last null values (only these which precede not null values).
Can I set something in mapping or handle it another, but simple way?

Here is a simple test code and mapping:


//save
hsession = factory.openSession();
t = hsession.beginTransaction();
OneDimensionalStringArrayBean odsab = new ad.persistence.OneDimensionalStringArrayBean();
odsab.setList2(new String[]{null,"3",null,null});
hsession.save(odsab);
long id = odsab.getId();
hsession.flush();
t.commit();
hsession.close();

//load
hsession = factory.openSession();
t = hsession.beginTransaction();
odsab = (OneDimensionalStringArrayBean) hsession.load(ad.persistence.OneDimensionalStringArrayBean.class,new Long(id));
String[] array = odsab.getArray2();
System.out.println("length:"+array.length);
for(int i=0;i<array.length;i++)
System.out.println(array[i]);
hsession.flush();
t.commit();
hsession.close();

Output is:
length:2
null
3

instead of:
length:4
null
3
null
null



<hibernate-mapping>
<class name="ad.persistence.OneDimensionalStringArrayBean" table="OneDimensionalStringArrayBean">
<id name="id" type="long" column="id" unsaved-value="none">
<generator class="identity" />
</id>
<array name="list2" table="OneDimensionalStringArrayBean_list2" cascade="all-delete-orphan" >
<key column="list_id" />
<index column="list_index" />
<element column="value" type="string" />
</array>
</class>
</hibernate-mapping>

I have the same problem.

Same here ... and in a way obvious. How should Hibernate now the length if it is omitting the null elements / values.

A simple workaround to access individual elements in the array is still possible:


Surely, if one is interested to get the whole array instead of individual elements then the same approach can be applied ...

Maybe this helps ...