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Forum locked This topic is locked, you cannot edit posts or make further replies.  [ 3 posts ] 
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 Post subject: Simple HQL on a collection
PostPosted: Fri Jan 20, 2006 8:28 am 
Regular
Regular

Joined: Wed Sep 21, 2005 1:37 pm
Posts: 53
Location: Montpellier - France
Hello,

I want to make a simple query, but I don't really understand how to do it in HQL.

in SQL :
Code:
select distinct user_id from GROUP_MEMBERS where group_id = ?


I want to retrieve 'primaryKey' for each user, member of the specified group.

Hibernate version: 3.1

Mapping documents:

Code:
<class name="UserBMP" table="USERS" node="user">
<id name="primaryKey" column="user_id" type="java.lang.String" node="@user_id" unsaved-value="null"/>
...
<set name="groups" table="GROUP_MEMBERS" fetch="select" lazy="true" embed-xml="false" cascade="persist,save-update" inverse="true">
<key column="user_id"/>
<many-to-many column="group_id" class="GroupBMP" embed-xml="false" fetch="select"/>
</set>
</class>


Thanks


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 Post subject:
PostPosted: Fri Jan 20, 2006 9:12 am 
Regular
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Joined: Wed Jun 29, 2005 11:14 pm
Posts: 119
Location: KĂžbenhavn
I assume you habe the group mapped properly but something like the following should do it (Remember HQL is case sensitive!)

Code:
"select distinct id from User where groups.id=?"


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 Post subject:
PostPosted: Fri Jan 20, 2006 12:12 pm 
Regular
Regular

Joined: Wed Sep 21, 2005 1:37 pm
Posts: 53
Location: Montpellier - France
I think the results are invalid because :

Quote:
java.lang.ClassCastException: $Proxy261
at org.hibernate.type.StringType.toString(StringType.java:44)
at org.hibernate.type.NullableType.toLoggableString(NullableType.java:169)
at org.hibernate.pretty.Printer.toString(Printer.java:65)
at org.hibernate.engine.QueryParameters.traceParameters(QueryParameters.java:256)
at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:149)
at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1127)
at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79)
at AbstractBean.findBy(AbstractBean.java:156)
at UserBean.ejbFindByGroup(UserBean.java:248)


and I just want to retrieve the 'user_id' string values.


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