Using a generator with composite-id

Dreamliner · **Joined:** Fri Nov 18, 2005 8:35 am **Posts:** 2

Hello,

I have composite id, made up of two properties. One of which is a foreign key in the table, and the other which isn't.

<composite-id name="id" class="persistence.MatchExpulsionsId">
<key-property name="matchId" type="int">
<column name="MATCH_ID" />
</key-property>
<key-property name="expulsionNo" type="int">
<column name="EXPULSION_NO" />
</key-property>
</composite-id>

So, here it is easy to have MATCH_ID, because it is a foreign key from another relation.

I would like to have EXPULSION_NO automatically generated (increment)...so that it now looks like:

<composite-id name="id" class="persistence.MatchExpulsionsId">
<key-property name="matchId" type="int">
<column name="MATCH_ID" />
</key-property>
<key-property name="expulsionNo" type="int">
<column name="EXPULSION_NO" />
<generator class="increment" />
</key-property>
</composite-id>

Is there anyway to achieve this, or is there a workaround?

Many thanks.

nathanmoon · **Posted:** Fri Nov 18, 2005 11:25 am

This FAQ might help you:

http://www.hibernate.org/117.html#A35

Dreamliner · **Joined:** Fri Nov 18, 2005 8:35 am **Posts:** 2

That did it...thanks.

singhal.ashwani · **Joined:** Thu Dec 22, 2005 7:57 am **Posts:** 1

i am also finding the same code ,
Would any one send me the source code for the same ?

Thanks
Ashwani

lalasap · **Joined:** Tue Feb 13, 2007 8:39 am **Posts:** 1

Hi Dreamliner,
You said that you solved this problem of having an increment class generator in composite-id. Could you please send the code for the same? I'm facing the same problem.

Thanks in advance.