Hibernate version: 3
Name and version of the database you are using: Oracle 10g

Hi guys,

I would like to add a metadata to "MyProperty" property as following, to specify whether this property is auditable or not (Audit Logging)

Mapping documents:

<hibernate-mapping>

<class name="path.Table" table="TABLE" schema="S">

<meta attribute="generated-class">path.gen.TableGen</meta>
<meta attribute="scope-class" inherit="false">public abstract</meta>
<meta attribute="scope-field">protected</meta>

<id name="tableId" type="long">
<column name="TABLE_ID" precision="10" scale="0" />
<generator class="sequence">
<param name="sequence">s.TABLE_ID</param>
</generator>
</id>

<version name="version" column="VERSION"/>

<property name="myProperty" type="string" column="MY_PROPERTY">
<meta attribute="auditable">true</meta>
</property>

<property name="anotherProperty" type="string" column="ANOTHER_PROPERTY">
</property>

</class>
</hibernate-mapping>

################

In a test class, I try to get the value of my metadata as following

SessionFactory sf = (SessionFactory)applicationContext.getBean("sessionFactory");

Configuration cfg = sf.getConfiguration();

PROBLEM : there is no getConfiguration() method for SessionFactory object, so the code next doesn't work

PersistentClass pc = cfg.getClassMapping(Table.class.getName());

for ( Iterator it = pc.getPropertyIterator() ; it.hasNext() ; ) {
Property p = (Property) it.next();
MetaAttribute ma = p.getMetaAttribute("auditable");
logger.debug(ma.getValue());
}

As my sessionFactory bean is a LocalSessionFactoryBean class (and have a getConfiguration() method), I tried to cast my SessionFactory as LocalSessionFactoryBean, but I obtain a castException

################

I also tried something like that to get a Configuration without using SessionFactory

Configuration cfg = new Configuration();
cfg.addResource("path/Table.hbm.xml");
...
logger.debug(ma.getValue());

It works fine, but as I have more than 100 *.hbm.xml files, this solution doesn't look optimal to me, and why bypass SessionFactory... there is probably a way to get the config from it, or at least a clever way to define my Configuration

################

I also thought about creating a Configuration bean in my applicationContext, but I didn't figured out how to give it access to my 100 *.hbm.xml files


At this point I have no more idea, so please help, any idea would be good.
Thanks a lot

why dont you just keep the Configuration around in the same place as you have your SessionFactory.

I'm not sure to understand what you mean, if you can explain a bit more...
Thanks

how do you get the SessionFactory ?

I assume by some lookup method or injection stuff.

Do the same for the Configuration.

e.g. HibernateUtil.getConfiguration()

OK I understand, that was like the third idea I posted
I created a bean which is a "org.hibernate.cfg.Configuration" class, and get it in my test class using applicationContext.getBean("configuration")
I made it work in my test adding a ressource to my configuration object got from my context

cfg.addResource("path/Table.hbm.xml");

but the thing is that I would like to list the ressources directly in my applicationContext.xml file, and as there is not setter to specify a list of ressources to my configuration bean, I still don't know how to do.
I probably just miss a little thing in the doc... argh !

i think you are looking for the spring forum, this is not hibernate specific/related.

oki, I finally found a solution, creating a bean "configuration" in my applicationContext that extends the Configuration class to create the method I would like to use
it works, but I'm not really happy with that, so, let's try on spring forum if there is a solution more simple
thanks a lot