Hi !!
If I do this:

Session s = getSession();
Country c1 = s.load(Country.class, new Integer(1));
Country c2 = s.load(Country.class, new Integer(1));

c1 and c2 will be the same instance (c1 == c2, I supose session is getting the instance from it's first-level cache). Is there a way to get different instances ?

Thanks !

Unless you create another session, there is no way, to my knowledge, to have a distinct java object. The fisrt level cache is help by the session.

I have not seen any solutions for getting two different instances when loading the same object. But on top of my head I can think of two possible workarounds:
1. You could try to close the session and reopen it before you load the second object.
2. You cold override the clone method and always do a clone when you load the objects.

Note. Even if c1 != c2, c1.equals(c2) should be true.

I too believe that closing and opening the session (or using another session) is the only way, but i can't see the point on having two different instances. Hibernate will complain if you modify each instance and save them...

Bye.

I won't save the two objects.
I'm using long session pattern. I have a grid with objects, select one from editing, change it, cancel the action, back to past page, and then make a find all to refill the grid. When I make a find all, I get all objects, including my dirty object.

You can call session.evict(dirtyObject) before reading it again.

This may be a long shot, but what about using Interceptors to clear out the dirty objects.

I haven’t used the Interceptor for this type of functionality, but you can detect dirty objects in the Interceptor, and the idea would then be to force Hibernate to reload the object.

The Interceptor documentation:
http://www.hibernate.org/hib_docs/v3/reference/en/html/events.html

Thanks !
One more question. How can I detect with an interceptor if an object is dirty and tell session to reload it from database ?