what's wrong with that :

In my class :

<class>

<id name="Id" type="java.lang.Integer">
<column name="ID" not-null="true" unique="true" sql-type="NUMBER(6)" />
<generator class="assigned" />
</id>
....
<joined-subclass name="Externe" table="EXTERNE" >
<key column="Id"/>
<property name="MontantFacturation" column="MONTANTFACTURATION"/>
</joined-subclass>

<joined-subclass name="Interne" table="INTERNE" >
<key column="Id"/>
<property name="SalaireMensuel" column="SALAIREMENSUEL"/>
</joined-subclass>

</class>



In my subclass :

<class name="fr.icdc.dei.fwk.sample.dto.Interne" table="INTERNE" schema="HIBERNATE">
<id name="Id" type="java.lang.Integer">
<column name="ID" not-null="true" unique="true" sql-type="NUMBER(6)" />
<generator class="assigned" />
</id>
<property name="SalaireMensuel" type="java.math.BigDecimal">
<column name="SALAIREMENSUEL" not-null="false" sql-type="NUMBER(8,2)" />
</property>
</class>
</hibernate-mapping>


AND



<class name="fr.icdc.dei.fwk.sample.dto.Externe" table="EXTERNE" schema="HIBERNATE">
<id name="Id" type="java.lang.Integer">
<column name="ID" scale="6" precision="0" not-null="true" unique="true" sql-type="NUMBER" />
<generator class="assigned" />
</id>
<property name="MontantFacturation" type="java.math.BigDecimal">
<column name="MONTANTFACTURATION" not-null="true" sql-type="NUMBER(8,2)" />
</property>
</class>
</hibernate-mapping>



I got that:
Initial SessionFactory creation failed
java.lang.ExceptionInInitializerError
at fr.icdc.dei.fwk.test.HibernateUtil.<clinit>(HibernateUtil.java:22)
at fr.icdc.dei.fwk.test.Test.main(Test.java:15)
Caused by: org.hibernate.MappingException: Error reading resource: fr/icdc/dei/fwk/sample/dto/Ressource.hbm.xml
at org.hibernate.cfg.Configuration.addResource(Configuration.java:447)
at org.hibernate.cfg.Configuration.parseMappingElement(Configuration.java:1392)
at org.hibernate.cfg.Configuration.parseSessionFactory(Configuration.java:1364)
at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:1346)
at org.hibernate.cfg.Configuration.doConfigure(Configuration.java:1313)
at org.hibernate.cfg.Configuration.configure(Configuration.java:1241)
at org.hibernate.cfg.Configuration.configure(Configuration.java:1227)
at fr.icdc.dei.fwk.test.HibernateUtil.<clinit>(HibernateUtil.java:16)
... 1 more
Caused by: org.hibernate.MappingException: duplicate import: Externe
at org.hibernate.cfg.Mappings.addImport(Mappings.java:101)
at org.hibernate.cfg.HbmBinder.bindPersistentClassCommonValues(HbmBinder.java:540)
at org.hibernate.cfg.HbmBinder.bindClass(HbmBinder.java:487)
at org.hibernate.cfg.HbmBinder.bindJoinedSubclass(HbmBinder.java:758)
at org.hibernate.cfg.HbmBinder.handleJoinedSubclass(HbmBinder.java:1791)
at org.hibernate.cfg.HbmBinder.createClassProperties(HbmBinder.java:1732)
at org.hibernate.cfg.HbmBinder.bindRootPersistentClassCommonValues(HbmBinder.java:317)
at org.hibernate.cfg.HbmBinder.bindRootClass(HbmBinder.java:235)
at org.hibernate.cfg.HbmBinder.bindRoot(HbmBinder.java:151)
at org.hibernate.cfg.Configuration.add(Configuration.java:358)
at org.hibernate.cfg.Configuration.addInputStream(Configuration.java:395)
at org.hibernate.cfg.Configuration.addResource(Configuration.java:444)
... 8 more
Exception in thread "main"




what's wrong?

You have two classes (one a joined-subclass) named Externe which is causing the conflict. By default, Hibernate assumes that all class names, regardless of package, will be unique and allows you to simplify the Query language statements by just using the unqualified class name. If you truely have two classes with the same name, Externe and fr.icdc.dei.fwk.sample.dto.Externe, then you can specify auto-import=false and it will use the fully qualified class names.

You should also look at the docs for <import> configuration as well.

Note: I haven't had to use this myself so I'm not sure what other side-effects this may cause.

but Extern is my subclass I have mapped it in a hbm.xml file.

It is the same file. I don't understand what to do?

You should probably read more about joined subclasses. If it's the same class, you don't need to also map it as a <class>. A joined-subclass is a top-level mapping.

thanks I have just find this soluce thanks

And now How can I precise the sql-type for the property?

ok ok I find it

this is my java file of one subclass :




package fr.icdc.dei.fwk.sample.dto;


public class Externe extends Ressource implements java.io.Serializable {

// Fields

private java.lang.Integer Id;
private java.math.BigDecimal MontantFacturation;


// Constructors

/** default constructor */
public Externe() {
}

/** constructor with id */
public Externe(java.lang.Integer Id) {
this.Id = Id;
}




// Property accessors
/**

*/

public java.lang.Integer getId () {
return this.Id;
}

public void setId (java.lang.Integer Id) {
this.Id = Id;
}
/**

*/

public java.math.BigDecimal getMontantFacturation () {
return this.MontantFacturation;
}

public void setMontantFacturation (java.math.BigDecimal MontantFacturation) {
this.MontantFacturation = MontantFacturation;
}




}


is it correct?