Folks,

I am trying to map to my own classes instead of using the built in mapping classes:

<property name="exp" column="EXP" type="myclasses.Exp"/>

Are there any special requirements of the myclasses.Exp class? (I can make it work by mapping to a string.)

At run time, I get a desrialization error.

Thanks,
Dave

My class does implement Serializable.

Read the documentation, you want a UserType.

Thanks, Christian. I have been through Hibernate in Action, the java doc, and the documentation at:

http://www.hibernate.org/hib_docs/v3/re ... pes-custom

The documentation states:

To implement a custom type, implement either org.hibernate.UserType or org.hibernate.CompositeUserType and declare properties using the fully qualified classname of the type.

So, my question is this...

Before I embark on the effort to write 9 of the 11 methods (I already have hashcode and equals ) required by the UserType interface for my 100 or so custom classes, is there an easier way? This isn't insurmountable, but likewise it certainly isn't trivial, and I'm eager to start on the actual mapping activity.

Thanks again,
Dave

Are you sure that you aren't really trying to map many-to-one (and related) associations?

100+ custom types seems excessive.


For example:



You don't need a custom UserType for any of that. I appologize if this isn't the case for you, but it seems like you might be headed down the wrong path here.