On http://www.hibernate.org/200.html it says the following:

"mixed" table-per-hierarchy / table-per-subclass inheritance mapping strategy, and table-per-subclass inheritance with a discriminator column

There is also a note indicating that this functionality is already implemented in Hibernate3. However, the DTD does not allow discriminator-value to be used with joined-subclass element.

How do I use table-per-subclass strategy with discriminator-value?
Thanks.

Alec

hmm, I tried the last example on that link and I got this error:
aused by: org.xml.sax.SAXParseException: Attribute "outer-join" must be declared for element type "join".

I am using this DTD:
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd" >

Am I using the right DTD or the DTD is inconsistent?
Thanks.

Alec

Gavin, one more question.

Consider the following scenario, which I copied from the link that you just sent me:
<class name="Foo" table="foos" discriminator-value="0">
<id name="id">...</id>
<discriminator column="type" type="int"/>
<property name="name"/>
<subclass name="Bar" discriminator-value="1">
<join table="bars" outer-join="false">
<key column="fooId"/>
<property name="amount"/>
</join>
</subclass>
</class>


When a new Bar object is persisted in the database it forces a new row to be inserted in the foo table. Can I disable this?

The reason for disabling this is that in my case the "bar" table INHERITs from the "foo" table (SQL 99 feature), so when I insert a row in the "bar" table it automatically creates a corresponding row in the "foo" table. Therefore, I don't want Hibernate to explicitly insert a row in table "foo".

Thanks.
Alec

No, not possible.

FYI, the outer-join attribute is replaced by the fetch attribute in this release.

Actually, it is possible, just write a custom EntityPersister. (It might help to work off the HB3 codebase for this.)