Hibernate version:2.1.6

Mapping documents:

<id
name="id"
column="ID"
type="int"
unsaved-value="none"
>


Name and version of the database you are using:MySQL 4.0.21

Hi guys,

I am using xDoclet to export schema into MySQL DB like below:

<target name="schemaexport" depends="generate.jar" description="Exports all hbm.xml files in {src.dir}">
<echo message="Run the schema export for all hbm.xml files in ${src.dir}"/>
<path id="schemaexport.classpath">
<fileset dir="${web.dir}/WEB-INF/lib">
<include name="*.jar"/>
</fileset>
<fileset dir="${src.dir}/catalog/model/businessobject">
<include name="*.jar"/>
</fileset>
</path>

<taskdef
name="schemaexport"
classname="net.sf.hibernate.tool.hbm2ddl.SchemaExportTask"
classpathref="schemaexport.classpath">
</taskdef>

<schemaexport
properties="${src.dir}/catalog/hibernate.properties"
quiet="no"
text="no"
drop="no"
output="${src.dir}/catalog/schema-export.sql"
>
<fileset dir="${src.dir}">
<include name="**/*.hbm.xml"/>
</fileset>
</schemaexport>
</target>

But I want my id type to be tinyint or bigint in some table. As in the mapping document, I set the type to int but in MySql DB, it's int(11). Pls help, Thanks !

prettyhandling

sql-type

Hi,

U mean I gotta implement like this post?

http://forum.hibernate.org/viewtopic.ph ... 64#2220464

No, just set sql-type on your property. Please read the manual.