Hibernate version:
Hibernate 2.0
Mapping documents:
Table client mapping file :
<hibernate-mapping>
<class
name="myPackage.Client"
table="CLIENT"
>
<id
name="id"
type="long"
column="ID"
unsaved-value="0"
>
<generator class="seqhilo">
<param name="sequence">CLIENT_SEQ</param>
<param name="max_lo">0</param>
</generator>
</id>

<discriminator
column="CODE_DISCRIMINANT"
type="java.lang.String"
/>

<property
name="qualite"
type="java.lang.String"
column="QUALITE"
unique="true"
length="1"
/>
<property
name="dateCreation"
type="java.sql.Timestamp"
column="DATE_CREATION"
length="7"
/>
<property
name="dateModif"
type="java.sql.Timestamp"
column="DATE_MODIF"
length="7"
/>
<set
name="dossierVoyages"
lazy="true"
inverse="true"
>
<key>
<column name="CLIENT" />
</key>
<one-to-many
class="myPackage.DossierVoyage"
/>
</set>

<subclass
name="myPackage.Interlocuteur"
discriminator-value="INTERLOCUTEUR">
<property
name="prenom"
type="java.lang.String"
column="PRENOM"
not-null="true"
unique="true"
length="30"
/>
<property
name="nom"
type="java.lang.String"
column="NOM"
not-null="true"
unique="true"
length="30"
/>
</subclass>
</class>
</hibernate-mapping>

Name and version of the database you are using:
Oracle 8i


- the mapping file represent the table CLIENT.
Containing a sublass : Interlocuteur
and a one-to-many relation to table DossierVoyage

question :
How can i do a multi criteria method with API Criteria on Interlocuteur.class (subclass of CLIENT) with Expression on :
- DossierVoyage.anyProperty
- Interlocuteur.nom

cause the relation is on CLIENT not on Interlocuteur
so i dont have an associationPath to DossierVoyage from Interlocuteur.

anyone got an idea pls ?

thanks,
Franck