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ab99999
 Post subject: How do I get my java class to detect SQLException
PostPosted: Fri Aug 20, 2004 1:30 pm 
Newbie

Joined: Fri Aug 20, 2004 9:29 am
Posts: 3
Location: London, England
I have a general beginners question - how do I detect specific exceptions when I call dao.save() in Hibernate - specifically I have a unique index on a code column on my table and when I attempt to save a non-unique value it will give me a "Duplicate key" error in the stack dump - but dao.save()/Hibernate only seems to want to return Exception. Is there a way of getting more granular errors from the call?

.. and here's the code if you want to see.....

Hibernate version:2.1

Code between sessionFactory.openSession() and session.close():
try {
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();
Transaction txn = session.beginTransaction();
_RootDAO.initialize();
LoginDAO dao = new LoginDAO();
Login login = new Login();
login.setLoginNm("John Smith");
login.setLoginCd("js");
dao.save(login);
txn.commit();
session.close();
} catch (Exception e) {
System.out.println("main Exception " + e.toString());
}



Full stack trace of any exception that occurs:

could not insert: [com.test.hibernate.mapping.Login] main Exception net.sf.hibernate.JDBCException: could not insert: [com.test.hibernate.mapping.Login]
20-Aug-2004 18:19:58 net.sf.hibernate.JDBCException <init>
SEVERE: could not insert: [com.test.hibernate.mapping.Login]
java.sql.SQLException: Duplicate key or integrity constraint violation, message from server: "Duplicate entry 'js' for key 3"
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:1977)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1163)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1272)
at com.mysql.jdbc.Connection.execSQL(Connection.java:2236)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1741)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1588)
at net.sf.hibernate.persister.EntityPersister.insert(EntityPersister.java:528)
at net.sf.hibernate.persister.EntityPersister.insert(EntityPersister.java:432)
at net.sf.hibernate.impl.ScheduledIdentityInsertion.execute(ScheduledIdentityInsertion.java:29)
at net.sf.hibernate.impl.SessionImpl.doSave(SessionImpl.java:932)
at net.sf.hibernate.impl.SessionImpl.doSave(SessionImpl.java:857)
at net.sf.hibernate.impl.SessionImpl.saveWithGeneratedIdentifier(SessionImpl.java:775)
at net.sf.hibernate.impl.SessionImpl.save(SessionImpl.java:738)
at com.test.hibernate.mapping.base._BaseRootDAO.save(_BaseRootDAO.java:559)
at com.test.hibernate.mapping.base._BaseRootDAO.save(_BaseRootDAO.java:540)
at com.test.hibernate.mapping.base.BaseLoginDAO.save(BaseLoginDAO.java:60)
at com.mzuzu.test.hibernate.mapping.dao.LoginDAO.main(LoginDAO.java:81)
net.sf.hibernate.JDBCException: could not insert: [com.test.hibernate.mapping.Login]
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ernst_pluess
 Post subject:
PostPosted: Sat Aug 21, 2004 4:47 am 
Expert
Expert

Joined: Thu Jan 29, 2004 2:31 am
Posts: 362
Location: Switzerland, Bern
The signature of the save method is
Code:
public Serializable save(Object object)
                  throws HibernateException

catch (or cast to) a HibernateException and look for the causing exception by calling getCause().

HTH
Ernst
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ab99999
 Post subject:
PostPosted: Tue Aug 24, 2004 8:53 am 
Newbie

Joined: Fri Aug 20, 2004 9:29 am
Posts: 3
Location: London, England
Thanks - that works - although I've opted to ignore save() and go for saveOrUpdate() method in _RootDAO.java - and I've added some deadlock handling too....

Code:
protected void saveOrUpdate(Object obj) throws HibernateDuplicateKeyException, HibernateException {
      Transaction t = null;
      Session s = null;

      boolean deadlock = true;

      while (deadlock) {
          deadlock = false;
         try {
            s = getSession();
            t = beginTransaction(s);
            saveOrUpdate(obj, s);
            commitTransaction(t);
         } catch (HibernateException e) {
            if (null != t)
               t.rollback();
            String error = e.getCause().toString();
            if (error.indexOf("Deadlock") != -1) {
               deadlock = true;
            }
            if (error.indexOf("Duplicate key or integrity constraint violation") != -1) {
               throw new HibernateDuplicateKeyException(error);
            }
            throw e;
         } finally {
            closeSession(s);
         }
      } // while
   }
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tq
 Post subject:
PostPosted: Tue Aug 24, 2004 9:20 am 
Regular
Regular

Joined: Thu Aug 05, 2004 2:27 am
Posts: 54
Location: South Africa
sorry I miss the point of this loop, maybe you can clear it up for me.

after catching the exception and rolling back, you have
Code:
if (error.indexOf("Deadlock") != -1) {
               deadlock = true;
            }


then you throw e;
so what exactly does the boolean deadlock do?
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ab99999
 Post subject:
PostPosted: Tue Aug 24, 2004 9:31 am 
Newbie

Joined: Fri Aug 20, 2004 9:29 am
Posts: 3
Location: London, England
whoops - you're right ... it should read...

Code:
   protected void saveOrUpdate(Object obj) throws HibernateDuplicateKeyException, HibernateException {
      Transaction t = null;
      Session s = null;

      boolean deadlock = true;

      while (deadlock) {
          deadlock = false;
         try {
            s = getSession();
            t = beginTransaction(s);
            saveOrUpdate(obj, s);
            commitTransaction(t);
         } catch (HibernateException e) {
            if (null != t)
               t.rollback();
            String error = e.getCause().toString();
            if (error.indexOf("Duplicate key or integrity constraint violation") != -1) {
               throw new HibernateDuplicateKeyException(error);
            }
            if (error.indexOf("Deadlock") != -1) {
               deadlock = true;
            }
            else {
                throw e;
            }
         } finally {
            closeSession(s);
         }
      } // while
   }
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