Still many-to-one Problem help!!!

lesha · **Posted:** Mon Jul 19, 2004 11:46 am

Hi!
Inserting Mitspieler doesn't make a problem, but inserting a Tippgemeinschaft still does:
No persister for: java.lang.Long
A Mitspieler(Player) can have several Teams (Tippgemeinschaft) to manage and a Team must have an admin.

Hier is my mapping file:

Code:

<class name="tippspiel.Mitspieler" table="MITSPIELER"> 

       <id name="id" unsaved-value="null"> 
         <column name="ID" sql-type="bigint(20)" not-null="true"/> 
         <generator class="native"/> 
      </id> 

             
       <set name="adminTippgemeinschaften" inverse="true" lazy="true" cascade="all-delete-orphan"> 
            
            <key column="ADMIN_ID"/> 
            <one-to-many class="tippspiel.Tippgemeinschaft"/> 
         </set> </class> 


<class name="tippspiel.Tippgemeinschaft" table="TIPPGEMEINSCHAFT"> 
      <id name="id" type="long" unsaved-value="null"> 
         <column name="ID" sql-type="bigint(20)" not-null="true"/> 
         <generator class="native"/> 
      </id> 
       
       
      <many-to-one name= "adminId" class = "tippspiel.Mitspieler" column="ADMIN_ID" not-null="true" unique="true"/>        </class> 
 

Here are my Beans:

Code:

public class Mitspieler {
   private long id;
   private String name;
   private String email;
   private String passwort;
...}
public class Tippgemeinschaft {
   private long id;
   private String name;
   private long adminId;
...}

And this is how I try to insert Tippgemeinschaft:

Code:

Transaction tx = session.beginTransaction();

         Mitspieler tom = new Mitspieler();
         tom.setName("Benny");
         tom.setEmail("benny@gmx.de");
         tom.setPasswort("secret^4!");
         
         session.save(tom);
         tx.commit();
//Get Benny's Id = adminId (and cast it to long) ...
         
         Transaction tx3 = session.beginTransaction();

// I want Benny to admin this Team(Tippgemeinschaft):

         Tippgemeinschaft hsv = new Tippgemeinschaft();
         hsv.setName("HSV Fanclub");
         hsv.setAdminId(adminId);
         session.save(hsv);
         tx3.commit();

lorban · **Posted:** Mon Jul 19, 2004 2:12 pm

First, something looks strange:

you have defined your primary keys as primitive "long" in your bean classes but you set the unsaved value to "null" in the xml mapping. I'm not sure how Hibernate handles this but you should change the types to java.lang.Long or use for example "0" as unsaved value.

But the real problem is something else. Looks like you haven't completely understood how the many-to-one mapping is working. Have a closer look at chapter 6.8 of the manual.

In fact, you should change

Code:

private long adminId;

in the Tippgemeinschaft class for this:

Code:

private Mitspieler admin;

and change the getter/setter accordingly.

anthony · **Posted:** Mon Jul 19, 2004 3:38 pm

lesha,
please don't crosspost
http://forum.hibernate.org/viewtopic.php?t=932718

you have to know about java types....

lesha · **Posted:** Tue Jul 20, 2004 4:25 am

IT WORKS!!!
Thanks a lot!

Lena

P.S.Sorry for crossposting (never used a Forum before). But I learn fast ;)

anthony · **Posted:** Tue Jul 20, 2004 4:26 am

no pb but don't do it again ;)

hhale21 · **Joined:** Fri Jul 23, 2004 12:13 am **Posts:** 7

Hello, I encountered the same problem but after reading section 6.8 in the docs and this post I am still missing something.

I have basically the thing:

public class Mitspieler {
private long id;
private String name;
private String email;
private String passwort;
...}
public class Tippgemeinschaft {
private long id;
private String name;
private Mitspieler admin;
...}

Mitspieler tom = new Mitspieler();
tom.setName("Benny");
tom.setEmail("benny@gmx.de");
tom.setPasswort("secret^4!");
session.save(tom);
tx.commit();

Tippgemeinschaft hsv = new Tippgemeinschaft();
hsv.setName("HSV Fanclub");
hsv.setAdmin(tom);
session.save(hsv);
tx.commit();

session.save(hsv); always throws the exception -> No persister for: java.lang.Integer
All columns long.
What else could be the cause of this?