How to make the xml schema for PersistentEnum types?

raulseh · **Joined:** Fri Apr 02, 2004 2:19 pm **Posts:** 1

Sorry for my newie question but I haven't seen any example for that.

My PersistentEnum class:

Code:

package hospital.admin;

import net.sf.hibernate.PersistentEnum;

/**
 * @author raul
 *
 * To change the template for this generated type comment go to
 * Window&gt;Preferences&gt;Java&gt;Code Generation&gt;Code and Comments
 */
public class TipoUsuario implements PersistentEnum {
   private int code;
   private String name;

   public static final TipoUsuario ADMINISTRADOR =
      new TipoUsuario("Administrador");
   public static final TipoUsuario ADMINISTRACION =
      new TipoUsuario("Administracion");
   public static final TipoUsuario FARMACEUTICO =
      new TipoUsuario("Farmaceutico");
   public static final TipoUsuario MEDICO = new TipoUsuario("Medico");
   public static final TipoUsuario DIETISTA = new TipoUsuario("Dietista");

   private static int count = 0;

   private TipoUsuario(String name) {
      this.name = name;
      this.code = count++;
   }
   private TipoUsuario() {
      name = null;
      code = 0;
   }
   public static TipoUsuario fromInt(int code) {
      switch (code) {
         case 0 :
            return ADMINISTRADOR;
         case 1 :
            return ADMINISTRACION;
         case 2 :
            return FARMACEUTICO;
         case 3 :
            return MEDICO;
         case 4 :
            return DIETISTA;
         default :
            throw new RuntimeException("Unknown TipoUsuario code");
      }
   }

   /* (non-Javadoc)
    * @see net.sf.hibernate.PersistentEnum#toInt()
    */
   public int toInt() {
      // TODO Auto-generated method stub
      return code;
   }

   public String toString() {
      return name;
   }

}

the xml schema:

Code:

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
   "-//Hibernate/Hibernate Mapping DTD//EN"
   "http://hibernate.sourceforge.net/hibernate-mapping-2.0.dtd">

<hibernate-mapping>
    <class name="hospital.admin.TipoUsuario" table="tipousuario">
       <id name="code" type="long" unsaved-value="null">
                 <column name="TipoUsuario" not-null="true"/>
                 <generator class="uuid.string"/>
        </id>
        
        <property name="name" column="name" type="string"/>
        
    </class>

</hibernate-mapping>

the exception throwed:

Code:

net.sf.hibernate.PropertyNotFoundException: Object class hospital.admin.TipoUsuario must declare a default (no-argument) constructor
   at net.sf.hibernate.util.ReflectHelper.getDefaultConstructor(ReflectHelper.java:122)
   at net.sf.hibernate.persister.AbstractEntityPersister.<init>(AbstractEntityPersister.java:558)
   at net.sf.hibernate.persister.EntityPersister.<init>(EntityPersister.java:715)
   at net.sf.hibernate.persister.PersisterFactory.createClassPersister(PersisterFactory.java:41)
   at net.sf.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:137)
   at net.sf.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:750)
   at hospital.SessionManager.updateParams(SessionManager.java:116)
   at hospital.SessionManager.<init>(SessionManager.java:77)
   at hospital.ApplicationHospital.<init>(ApplicationHospital.java:46)
   at hospital.ApplicationHospital.getInstance(ApplicationHospital.java:52)
   at hospital.ApplicationHospital.main(ApplicationHospital.java:67)
No se ha podido obtener acceso a la base de datos
Exception in thread "main" java.lang.NullPointerException
   at hospital.ApplicationHospital.main(ApplicationHospital.java:69)

In the example on manual for PersistentEnum class Color I haven't seen any default constructor, so I think Im doing something wrong.

If I create a default constructor Hibernates throws me other exception telling me I must declare the getter and setter methods por the properties. And I haven't seen any getter/setter method in Color example class.

Could someone tell me how to correct this problem??

thanks in advance!

emmanuel · **Posted:** Mon Apr 05, 2004 3:51 am

TipoUsuario is a property persister, not a class to map

Code:

It is done to map an enum into one column.