Hi all,

I understand that you can use <composite-element> to map table's column from the join-table to either ends of the many-to-many relationship. But approach will only give either end entity a one-to-many relationship to the components that contains data collected from the join-tables. What I really want is to have properties of one ends of the many-to-many relationship, to be automatically load from the join-table given the opposite end of the relationship. For example,

A(x,y,z)*<-->*B => A<-*AB(x,y,z)*->B

so if 'a' is an instant of A, and 'b' is an instant of B. And a<-->b are links, i.e. associated, then I want a's properties to be automatically loaded

e.g. A.x==AB.x; A.y==AB.y; A.z==AB.z given instant of A and B are associated.

A real world implication is, having a Code entity that has many-to-many relationship with Dictionary entity. Code has id and image properties, where image is being store in the join-table. So if instance of Code is assinged with an instance of Dictionary, then automatically the image property of Code will be load from the associated row and column that reflex the instance of Code and Dictionary association, i.e. or assignment.

Thanks in advance for any help or ideas,

--danny

use unmapped getter/setter doing the job

Hi,

Can you give further explaination, or any example?

Thanks,

--danny

Hi,

What do you mean by unmapped getter/setter? can you give further explaination, or some sample codes? Right now, I am thinking creating a one-to-one relationshipt between Dictionary and Code to associate code to a DEFAULT Dictionary, and buy having Code implement the onLoad method of the LifeCycle interface to navigate the list of the mapped composite-element(s) to its many-to-one association with Dictionary end, and compare this Dictionay instant against the one-to-one instant of the Dictionary, if they are match then the associated composite-element properties will be use to load the Code's unmapped getter/setter. But this seem to be quite some work to scan the entire Dictionary, and so I wonder if there is any other way to do the job better and faster?

Thanks,

--danny