Hibernate Community • View topic - How to use generator sequence with User Types

View unanswered posts | View active topics

Board index » Hibernate & Java Persistence » Hibernate Users

All times are UTC - 5 hours [ DST ]

How to use generator sequence with User Types

Page 1 of 1

[ 3 posts ]

Previous topic | Next topic

Author

Message

domingos

Post subject: How to use generator sequence with User Types

Posted: Tue Oct 14, 2003 4:09 pm

Newbie

Joined: Tue Oct 14, 2003 3:47 pm
Posts: 1
Location: Brasil - Rio de Janeiro

When I use an id that is a User Type with generator sequence I receive an exception on inserting an object.

net.sf.hibernate.id.IdentifierGenerationException: this id generator generates long, integer, short
at net.sf.hibernate.id.IdentifierGeneratorFactory.get(IdentifierGeneratorFactory.java:33)
at net.sf.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:65)
at net.sf.hibernate.impl.SessionImpl.save(SessionImpl.java:614)

I'm using Hibernate 2.0. Is it a bug or an unimplemented feature?

Domingos Fernando

Top

gavin

Post subject:

Posted: Tue Oct 14, 2003 7:48 pm

Hibernate Team

Joined: Tue Aug 26, 2003 12:50 pm
Posts: 5130
Location: Melbourne, Australia

you must use a custom IdentifierGenerator, of course.

Top

dberansky

Post subject:

Posted: Fri Dec 12, 2003 9:56 pm

Regular

Joined: Wed Sep 10, 2003 2:26 pm
Posts: 56
Location: San Diego, CA

I"ve run into the same problem.

All my UserType does is take a numberic id and convert it into a numeric string. I could be mistaken, but in theory, there is nothing in this scenario that precludes using the native generator. Am I right? Why can't this be doable if the UserType returns an iteger sql type from sqlTypes()?

Dmitry

Top

Page 1 of 1

[ 3 posts ]

Board index » Hibernate & Java Persistence » Hibernate Users

All times are UTC - 5 hours [ DST ]

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum