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 Post subject: Hibernate creates wrong sql query
PostPosted: Tue Sep 16, 2014 1:00 pm 
Newbie

Joined: Tue Sep 16, 2014 12:55 pm
Posts: 1
Hey!
I'm trying to extend my database program with a function to execute any hql query. I'm almost done with it but I get an error on the following process.

Code:
select p.reviews, p.title from Product p


This hql query is converted in an sql query as following:

Code:
Hibernate: select . as col_0_0_, product0_.title as col_1_0_, reviews1_.account_number as account_1_2_, reviews1_.product_id as product_2_2_, reviews1_.points as points3_2_, reviews1_.review as review4_2_ from dbprak12.view_product_meta product0_ inner join dbprak12.view_customer_evaluates reviews1_ on product0_.product_id=reviews1_.product_id


As you can obviously see, there will be thrown an error with sql state code 42601. Because " . as col_0_0_..." isn't correct syntax. But I don't understand why hibernate creates this sql query.

I use the following two xml mappings:

Product.hbm.xml
Code:
<!DOCTYPE hibernate-mapping PUBLIC
       "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
       "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>

   <class name="media.definitions.Product" table="dbprak12.view_product_meta">
      <id name="asin" column="product_id">
         <generator class="native" />
      </id>
      <property name="title" column="title" />
      <property name="avgRating" column="rating" />
      <property name="salesRank" column="sales_rank" />
      <property name="picUrl" column="picture" />
      <set name="reviews" cascade="all" inverse="true" lazy="true">
          <key column="product_id" />
          <one-to-many class="media.definitions.Review" />
       </set>
      <set name="categories" table="dbprak12.view_product_in_category" inverse="false" lazy="true" fetch="select" cascade="all">
         <key column="product_id" />
         <many-to-many column="category_id" class="media.definitions.Category" />
      </set>
      <joined-subclass name="media.definitions.Book" table="dbprak12.view_book">
         <key column="product_id" />
         <property name="isbn" column="isbn" />
         <property name="publishers" column="publisher" />
         <property name="pubDate" column="publication" />
         <property name="pages" column="pages" />
      </joined-subclass>
      <joined-subclass name="media.definitions.DVD" table="dbprak12.view_dvd">
         <key column="product_id" />
         <property name="format" column="fformat" />
         <property name="regionCode" column="region_code" />
         <property name="runningTime" column="running_time" />
      </joined-subclass>
      <joined-subclass name="media.definitions.Music" table="dbprak12.view_cd">
         <key column="product_id" />
         <property name="labels" column="label" />
         <property name="releaseDate" column="release_date" />
      </joined-subclass>
   </class>

</hibernate-mapping>


Review.hbm.xml
Code:
<!DOCTYPE hibernate-mapping PUBLIC
       "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
       "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>

  <class name="media.definitions.Review" table="dbprak12.view_customer_evaluates">
     <composite-id>
        <key-property name="accountNumber" column="account_number" />
        <key-many-to-one name="product" class="media.definitions.Product" lazy="false">
           <column name="product_id"></column>
        </key-many-to-one>
     </composite-id>
     <property name="rating" column="points" />
     <property name="content" column="review" />
  </class>

</hibernate-mapping>


I hope, that someone can help me. Thanks in advance!

Lukas


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