Dear Hibernate Team,

I'm getting the following Hibernate Exception, anyone knows about it?

Foreign key (FK_1h1baebylkp55202kt9spbbns:DUMMYTABLE [SIZE])) must have same number of columns as the referenced primary key (DUMMYTABLE [SIZE,idx])

This is my hibernate mapping file:

<hibernate-mapping>
<class name="DummyTable" table="DUMMYTABLE">
<id name="size" type="java.math.BigInteger">
<column name="SIZE" />
<generator class="assigned" />
</id>
<list name="values" inverse="false" table="DUMMYTABLE" lazy="true" access="field">
<key>
<column name="SIZE" />
</key>
<list-index></list-index>
<element type="javax.xml.bind.JAXBElement&lt;java.util.List&lt;java.lang.Double&gt;&gt;">
<column name="VALUES" />
</element>
</list>
<property name="xargument" type="java.lang.String">
<column name="XARGUMENT" />
</property>
<property name="yargument" type="java.lang.String">
<column name="YARGUMENT" />
</property>
</class>
</hibernate-mapping>


And this is the java class:

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "dummyTable", propOrder = {
"size",
"values"
})
public class DummyTable {

@XmlElement(name = "Size")
protected BigInteger size;
@XmlElementRef(name = "Values", namespace = "<my-own-name-space>", type = JAXBElement.class)
protected List<JAXBElement<List<Double>>> values;
@XmlAttribute(name = "Xargument", required = true)
protected String xargument;
@XmlAttribute(name = "Yargument", required = true)
protected String yargument;

//getters and setters....
}

Thanks a lot!