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 Post subject: @SecondaryTable duplicate rows
PostPosted: Wed May 30, 2012 6:57 am 
Newbie

Joined: Wed May 30, 2012 6:35 am
Posts: 1
Hi,

I'd like to set up this:

@Entity
@Table(name = "A", uniqueConstraints = {})
@org.hibernate.annotations.Table(appliesTo = "B", indexes = {})
@SecondaryTable(name = "AA", pkJoinColumns = {@PrimaryKeyJoinColumn(columnDefinition = "A_ID", name = "A_ID")})
class A {

@Column(name = "A_1", nullable = false)
Integer a1;

@Column(name = "A_1", table = "AA", nullable = false)
private Integer aa1;

public void setVirtualRamInMb(final Integer n)
{
this.a1 = n;
this.aa1 = n;
}

@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = "A_B", joinColumns = {@JoinColumn(name = "A_ID")}, inverseJoinColumns = {@JoinColumn(name = "B_ID")})
List<B> bs;
}

@Entity
@Table(name = "B")
@SecondaryTable(name = "A_B", pkJoinColumns = {@PrimaryKeyJoinColumn(columnDefinition = "B_ID", name = "B_ID")})
@org.hibernate.annotations.Table(appliesTo = "B")
class B {

@Column(name = "b1", nullable = true)
private long b1;

@Column(name = "ab1", table = "A_B", nullable = true)
private long ab1;


public void setSize(final long n)
{
this.b1 = n;
this.ab1 = n;
}

@ManyToMany(mappedBy = "bs", fetch = FetchType.LAZY)
private List<A> as;
}

when creating a B object and adding it to a A object, in the table A_B I end up with two results instead of one. In one the relation is ok but the ab1 is 0 (default) in the other the relation with A is null but ab1 is ok.

Is this the expected behavior?

PS: I can provide a simple example (maven) with a main to show it up.

Thanks.

Regards.

ssedano.


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