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Forum locked This topic is locked, you cannot edit posts or make further replies.  [ 2 posts ] 
Author Message
 Post subject: JPA with hibernate - createEntityManagerFactory throws excep
PostPosted: Mon Oct 04, 2010 11:56 am 
Newbie

Joined: Mon Oct 04, 2010 10:58 am
Posts: 1
Hello,
I am new to hibernate and JPA. I am trying to get a basic prototype working. There are two classes - Bid.java and Item.java (code below)


package com.Test;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;

@Entity
public class Bid {

private Long id;
private String name;

public void setId(Long id) {
this.id = id;
}

@Id
@GeneratedValue
public Long getId() {
return id;
}

@Override
public String toString() {
return "Item [id=" + id + ", name=" + name + "]";
}

public void setName(String name) {
this.name = name;
}

public String getName() {

return name;

}

}
====

Item.java

Package com.Test;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;


@Entity
public class Item {

private Long id;
private String name;

public void setId(Long id) {
this.id = id;
}

@Id
@GeneratedValue
public Long getId() {
return id;
}

@Override
public String toString() {
return "Item [id=" + id + ", name=" + name + "]";
}

public void setName(String name) {
this.name = name;
}



public String getName() {

return name;

}

}
=========================

This is my persistence.xml file

<persistence xmlns="http://java.sun.com/xml/ns/persistence"

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/ ... ce_2_0.xsd"

version="2.0">

<persistence-unit name="manager1">

<provider>org.hibernate.ejb.HibernatePersistence</provider>

<!-- not necessary to specify each class

hibernate searches even in non EE environments.

<class>com.test.Bid</class>

-->

<properties>

<property name="hibernate.archive.autodetection" value="class, hbm"/>

<property name="hibernate.show_sql" value="true"/>

<property name="hibernate.format_sql" value="true"/>

<property name="hibernate.connection.driver_class" value="net.sourceforge.jtds.jdbc.Driver"/>

<property name="hibernate.connection.url" value="jdbc:jtds:sqlserver://3.10.10.99:1433;databaseName=Test;"/>

<property name="hibernate.connection.username" value="sa"/>

<property name="hibernate.connection.password" value="sa">

<property name="hibernate.connection.pool_size" value="0"/>



<property name="hibernate.dialect" value="org.hibernate.dialect.SQLServerDialect"/>

<property name="hibernate.max_fetch_depth" value="3"/>



<property name="hibernate.hbm2ddl.auto" value="update"/>

<!--

* validate: validate the schema, makes no changes to the database.

* update: update the schema.

* create: creates the schema, destroying previous data.

* create-drop: drop the schema at the end of the session.

-->

</properties>

</persistence-unit>

</persistence>
===========================

I am trying to run this Junit test:

ublic class AppTest extends TestCase {

public AppTest(String testName) {

super(testName);

}



public static Test suite() {

return new TestSuite(AppTest.class);

}



public void testJPA() throws Exception {

EntityManagerFactory emf = Persistence

.createEntityManagerFactory("manager1");

EntityManager em = emf.createEntityManager();

EntityTransaction tx = em.getTransaction();

tx.begin();



Item item = new Item();

item.setName("this is a test name for the item using JPA");

Bid bid = new Bid();

bid.setName("somename");



em.persist(item);

em.persist(bid);

tx.commit();

List<Bid> bids = em.createQuery("from Bid").getResultList();



for(Bid currentBid : bids) {

System.out.println(currentBid);

}

em.close();

emf.close();



}

}
=========

I am getting this error: javax.persistence.PersistenceException: No Persistence provider for EntityManager named manager1
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32)
at AppTest.testJPA(AppTest.java:42)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at junit.framework.TestCase.runTest(TestCase.java:154)
at junit.framework.TestCase.runBare(TestCase.java:127)
at junit.framework.TestResult$1.protect(TestResult.java:106)
at junit.framework.TestResult.runProtected(TestResult.java:124)
at junit.framework.TestResult.run(TestResult.java:109)
at junit.framework.TestCase.run(TestCase.java:118)
at junit.framework.TestSuite.runTest(TestSuite.java:208)
at junit.framework.TestSuite.run(TestSuite.java:203)
at org.eclipse.jdt.internal.junit.runner.junit3.JUnit3TestReference.run(JUnit3TestReference.java:130)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:460)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:673)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:386)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:196)

Can you please tell me if I am missing something here? Does the persistence.xml have to be in a specific folder for this to work? Any pointers/guidance will be helpful.

Thanks.


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 Post subject: Re: JPA with hibernate - createEntityManagerFactory throws excep
PostPosted: Tue Oct 05, 2010 6:06 am 
Beginner
Beginner

Joined: Fri Nov 14, 2008 7:34 pm
Posts: 24
usually META-INF\persistence.xml


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